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Jlenok [28]
2 years ago
8

PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS! Are the images convex or concave polygons?

Mathematics
1 answer:
svp [43]2 years ago
5 0

Answer:

concave polygones

Step-by-step explanation:

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Match the real-world descriptions with the features they represent within the context of Melissa's garden. Not all tiles will
musickatia [10]
Can’t see photo so I can answer
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3 years ago
Given that a:b:c= 20 : 35 : 15, a) simplify a : b:c, b) find a:b,
Furkat [3]

Answer:

a) 4:7:3

b) 4:7 / 20:35

c) 3:7 / 15:35

4 0
2 years ago
Pls hurry
AlladinOne [14]

Step-by-step explanation:

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29Pls hurry

Rafael writes an expression to represent "a number, n, decreased by thirty-one." Then he evaluates that expression if

n-29. Which statements are true about the expression and its evaluation? Check all that apply.

The correct expression is 31-n.

This is a subtraction expression.

This is an addition expression.

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29..

4 0
3 years ago
Read 2 more answers
the insurance company pays the forecast of 3900 prescriptions claims out of 4500 prescription claims submitted what is the rate
nadya68 [22]

Answer:

x=0.87  or   86.67%

13 prescription claims out of 15 are paid

Step-by-step explanation:

First we organize the data:

prescription claims submitted: 4500

Prescriptions: 3900

The rate of claims paid is calculated using the following formula:

x =\frac{Paid}{Total}

We know that:

Paid = 3900

Total = 4500

So

x =\frac{3900}{4500}

x =\frac{39}{45}

x =\frac{13}{15}

x=0.87

6 0
3 years ago
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = \frac{9}{7+9}\times (x)

                                      = \frac{9}{16}\times (x)

And the weight of zinc = \frac{7}{7+9}\times (x)

                                      = \frac{7}{16}\times (x)

If the weight of zinc = 31.5 kg

31.5 = \frac{7}{16}\times (x)

x = \frac{16\times 31.5}{7}

x = 72 kgs

Therefore, weight of copper = \frac{9}{16}\times (72)

                                               = 40.5 kgs

2). i). 2 : 3 = \frac{2}{3}

        4 : 5 = \frac{4}{5}

Now we will equalize the denominators of each fraction to compare the ratios.

\frac{2}{3}\times \frac{5}{5} = \frac{10}{15}

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Since, \frac{12}{15}>\frac{10}{15}

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = \frac{11}{19}

    19 : 21 = \frac{19}{21}

By equalizing denominators of the given fractions,

\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}

And \frac{19}{21}\times \frac{19}{19}=\frac{361}{399}

Since, \frac{361}{399}>\frac{231}{399}

Therefore, 19 : 21 > 11 : 19

iii). \frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}

             =\frac{3}{2}

     \frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}

              = \frac{4}{3}

Now we equalize the denominators of the fractions,

\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}

And \frac{4}{3}\times \frac{2}{2}=\frac{8}{6}

Since \frac{9}{6}>\frac{8}{6}

Therefore, \frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4} will be the answer.

IV). 1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}

                  =\frac{6}{5}\times \frac{3}{4}

                  =\frac{18}{20}

                  =\frac{9}{10}

Similarly, \frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}

                       =\frac{4}{15}                  

By equalizing the denominators,

\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}

Similarly, \frac{4}{15}\times \frac{20}{20}=\frac{80}{300}

Since \frac{270}{300}>\frac{80}{300}

Therefore, 1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}

V). If a : b = 6 : 5

     \frac{a}{b}=\frac{6}{5}

        =\frac{6}{5}\times \frac{2}{2}

        =\frac{12}{10}

  And b : c = 10 : 9

  \frac{b}{c}=\frac{10}{9}

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

7 0
3 years ago
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