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I am Lyosha [343]
2 years ago
15

When you apply increasing thermal energy to a certain material, it reaches a temperature of 50 degrees C. However, when it reach

es this temperature, applying more increasing thermal energy does not cause the temperature to rise. Which of the following best explains what is happening?
1. The system is having its heat leaking out that is not going into the material

2. The material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature

3. The material is made of a heat resistant alloy that is preventing the thermal energy from being fully absorbed

4. The material has already absorbed enough thermal energy and cannot absorb any more
Physics
1 answer:
Sergio039 [100]2 years ago
8 0

The material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.

<h3>What is latent heat?</h3>

Latent heat is defined as the thermal energy absorbed or released during a phase change of a substance.

Latent heat can also be explained as the energy in hidden form which is supplied or extracted to change the state of a substance without changing its temperature.

From the above explanation, we can conclude that, the material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.

Learn more about latent heat here: brainly.com/question/87248

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In triangle​ ABC, the angles A and B have the same​ measure, while the measure of angle C is 21degrees larger than the measure o
Lynna [10]
180 = 2x+x+21
159 = 3x
x = 53
Angle A = 53°
Angle B = 53°
Angle C = 53+21 = 74°
7 0
3 years ago
An electrostatic paint sprayer has a 0.17 m-diameter metal sphere at a potential of 25.0 kV that repels charged paint droplets o
Troyanec [42]

Answer:

q=0.236uC

Explanation:

From the question we are told that:

Diameter d=0.17m

Radius r=0.17/2=>0.085

Potential E=25.0kV

Generally the equation for Potential on spere is mathematically given by

E=\frac{1}{4 \pi e_0}*\frac{q}{r}

Therefore

q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}

Where

\frac{1}{4 \pi e_0}=9*10^9

Therefore

q=\frac{25*10^3*0.085}{(9*10^9}}

q=0.236uC

4 0
3 years ago
An astronaut shipwrecked on a distant planet with unknown characteristics is on top of a cliff, which she wishes to descend. She
alexandr402 [8]

Answer:

y = 9.64 m

Explanation:

This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented

The rock is released

         y = y₀ + V₀₁ t₁ - ½ g t₁²

In this case the speed starts is zero

         y = y₀ - ½ g t₁²

The rock ​​is thrown up

       y = y₀ + v₀² t₂ -½ g t₂²

The height that reaches the floor is zero

       y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²

We use the initial velocity with the equation

         v₂² = v₀₂² - 2 g y

At the point of maximum height v₂ = 0

         v₀₂ = √ (2 g y_{max})

        g (-t₁² + t₂²) = 2 √ (2 g y_{max}) t₂²

        g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3

        g (22.4675) = 25.2 √ g

        g² = 2²5.2 / 22.4675 g

        g = 1.12 m / s²

Having the value of g we can use any equation to find the height

        y = ½ g t₁²

       y = ½ 1.12 4.15²

        y = 9.64 m

5 0
3 years ago
A bullet with momentum of 2.8 kg·m/s [E] is traveling at a speed of 187 m/s. The mass of the bullet is: a) 67 g b) 15 g c) 0.067
Vesna [10]

Answer:

The mass of the bullet is 15 g.

(b) is correct option.

Explanation:

Given that,

Momentum = 2.8 kg m/s

Speed = 187 m/s

We need to calculate the mass of the bullet

Using formula of momentum

P = mv

m = \dfrac{P}{v}

Where, P = momentum

v = speed

Put the value into the formula

m = \dfrac{2.8}{187}

m = 0.015\ kg

m = 15\ g

Hence, The mass of the bullet is 15 g.

4 0
3 years ago
What kinds of bonds can happen between the elements of a compound
Anit [1.1K]
What kinds of bonds can happen between the elements of a compound?

<span>Covalent and Ionic</span>

4 0
3 years ago
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