Elastic collisions<span> are collisions in which both </span>momentum<span> and kinetic energy are conserved. </span><span>The total system kinetic energy before the collision equals the total system kinetic energy after the collision. We calculate as follows:
m1v1 = m1v1' + m2v2'
0.80(0.50) = (0.80)(0.80-1)/(0.80+1)(0.50) + 1v2'
v2' = 0.11
Hope this helps. Have a nice day.
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It can be said that most of the required information's are already given in the question.
Let us assume the speed of the passenger train = x
Speed of the freight train = y
x = y + 40
The second equation will be
6 * x = 10 * y
6x = 10y
Dividing both sides by 2, we get
3x = 5y
x = 5y/3
Putting the value of "x" in the first equation, we get
x = y + 40
5y/3 = y + 40
5y = 3y + 120
5y - 3y = 120
2y = 120
y = 60 mph
Putting the value of y in the first equation, we get
x = y + 40
= 60 + 40
= 100 mph
From the above deduction, we can conclude that the passenger train is traveling at 100 mph and the freight train is traveling at 60 mph.
F=M×A
F=3 ×15
F=45N
so the force is 45 N
M = mass of aluminium = 1.11 kg
= specific heat of aluminium = 900
= initial temperature of aluminium = 78.3 c
m = mass of water = 0.210 kg
= specific heat of water = 4186
= initial temperature of water = 15 c
T = final equilibrium temperature = ?
using conservation of heat
Heat lost by aluminium = heat gained by water
M ( - T) = m (T - )
(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)
T = 48.7 c
Circular motion is what an object has if it is moving around and around and around and around and around and around and around and around and around in a path that is a circle.
