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Shtirlitz [24]
2 years ago
11

What is an open circuit?

Physics
2 answers:
Igoryamba2 years ago
6 0

Answer: A

Explanation:

An open circuit is a circuit that has no current flowing through it. The reason no current can flow through is due to a significant disconnect between two points in the circuit. For example, a large portion of the wire is cut out.

I haven't done any circuit analysis yet, but current can still flow through a circuit even if there is a cut. But that cut has to be extremely small.

Ainat [17]2 years ago
4 0
Answer:

A

An open circuit is a circuit where the path has been interrupted or "opened" at some point so that current will not flow. An open circuit is also called an incomplete circuit.
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The emission of light from a radioisotope occurs during ? decay.
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Gamma

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Which of the following does not describe a scientific theory?
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A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi
nlexa [21]
In order to find the radius of the coin, we need to use:

Ac = V^2 r

In which,  
Ac = acceleration of the coin = 2.2 m/s^2 
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so,
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3 years ago
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To find the product of 183.5 and 10², move the decimal point in 183.5
S_A_V [24]

Answer:

Given :

To find the product of 183.5 and 10², move the decimal point in 183.5 _____ places to the right because 10² has _____ zeros.

To Find :

We need to fill the spaces.

Solution :

We know, when number with positive power of 10 is multiplied with another number we need to shift the number to the right hand side by the number of zeroes.

So, To find the product of 183.5 and 10², move the decimal point in 183.5 to right places to the right because 10² has two zeros.

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2 years ago
At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) A) 0.6976
soldier1979 [14.2K]

Answer:

The speed of the stone is 0.6138 c.

(B) is correct option.

Explanation:

Given that,

Mass of stone m= 0.6

Relativistic mass = 0.76

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Using formula of rest mass

m_{r}=\dfrac{m_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}

v^2=(\dfrac{m_{0}^2}{m_{r}^2}-1)c^2

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v=\sqrt{0.37673c^2}

v=0.6138c

Hence, The speed of the stone is 0.6138 c.

3 0
3 years ago
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