In simple words, smoothing can be defined as the circuit which is done to eliminate the ripple from the yield of a direct current power supply.
<u>Explanation:</u>
<u>Necessity of smoothing:</u>
- Smoothing can be also applied in the form of a capacitor that acts to decrease or level out variations in a signal. And these capacitors are mostly used after power supply in voltage.
- The yield DC voltage of a half-wave rectifier provided in the figure of a sinusoidal wave.
- In a method to provide a constant DC voltage from a corrected AC source, a filter or smoothing circuit is required.
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Answer:
Part a)
a = -9.81 m/s/s
Part b)
v = 0
Part c)
v = 9.81 m/s
Part d)

Explanation:
Part a)
During the motion of ball it will have only gravitational force on the ball
so here the acceleration of the ball is only due to gravity
so it is given as

Part b)
As we know that ball is moving against the gravity
so here the velocity of ball will keep on decreasing as the ball moves upwards
so at the highest point of the motion of the ball the speed of ball reduce to zero

Part c)
We know that the total time taken by the ball to come back to the initial position is T = 2 s
so in this time displacement of the ball will be zero



Part d)
at the maximum height position we know that the final speed will be zero
so we will have

here we have


The answer would be B.
Semantics means the study of words and their meanings.
Hope this helped!
It is because change in the Mass of the object balances the change in the Volume of the object equally...........
Answer:
(a) 16.5528 V
(b) 827.64 W
Explanation:
(a)
The formula for maximum emf produced in a coil is given as
E₀ = BANω.................. Equation 1
Where E₀ = maximum emf produced in the coil, B = magnetic Field, A = Area of the rectangular coil, N = number of turns, ω = angular velocity.
Given: B = 1.9 T, N = 44 turns, ω = 110 rad/s, A = 2×9 = 18 cm² = 18/10000 = 0.0018 m²
Substitute into equation 1
E₀ = 1.9(44)(110)(0.0018)
E₀ = 16.5528 V
(b)
Maximum power
P₀ = E₀²/R...................... Equation 2
Where R = Resistance.
Given: R = 50 ohms, E₀ = 16.5528 V
Substitute into equation 2
P₀ = 50(16.5528)
P₀ = 827.64 W