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gulaghasi [49]
2 years ago
13

Which figures will have a volume that is greater than 100 cubic units? Select two options.

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
5 0

Answer:

B and D

Step-by-step explanation:

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8×1+5×(1/10)+9×(1/1,000)
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8×1+5×(1/10)+9×(1/1000)
8+5×(.1)+9×(.001)
8+.5+.009
Answer is 8.509

7 0
3 years ago
What’s 12 1/6 converted into a decimal
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Answer:

12.167

Step-by-step explanation:

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Which of these is equivalent to 3-2
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I think the to left
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Which questions result in data that is categorical? Check all that apply.
Rasek [7]

Answer:

1,2,3,5

Step-by-step explanation:

1-Is your job as an IT administrator stressful?

2-What is your biggest source of stress?

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8 0
3 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
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