Answer:
3x + 11
Step-by-step explanation:
Remember BPEMDAS.
"Three times a number" is saying multiply 3 times a variable; in this case, <em>x</em>. So we have 3x
"The sun of 3x and 11" is saying add our 3x and 11, so: 3x + 11
Y-10=2x -16
2x-y = -16+10
2x - y = - 6 ( ax + by = c )
Answer: a) 1,600
b) 35,000
c) 120,000
<u>Step-by-step explanation:</u>
First, round each number to one significant digit (the first digit).
Then multiply them.
a) 17 --> rounds to 20
82 --> rounds to 80
20 x 80 = 2 x 8 with two zeros
= 1 6 0 0
b) 54 --> rounds to 50
671 --> rounds to 700
50 x 700 = 5 x 7 with three zeros
= 3 5 0 0 0
c) 207 --> rounds to 200
643 --> rounds to 600
200 x 600 = 2 x 6 with four zeros
= 1 2 0 0 0 0
Answer:
combined velocity of the system = 0.033 m/s.
Step-by-step explanation:
taking the bullet and block as single system since there is no external force involved momentum is conserved .
initial momentum of the bullet = mv
where m is the mass of bullet and v is velocity of bullet.
and initial momentum of block = 0 since its velocity is 0.
therefore initial momentum of the system = mv
= 0.005×40
= 0.2
when the bullet stick of together with the block let the combined velocity of the system be V
therefore applying conservation of momentum
mv = (M+m)V
0.2=(6+0.005)V
therefore V = 0.033 m/s
Answer:
3x^2 + 3 --> 6, 15, 30, 51
2x^2 - 1 --> 1, 7, 17, 31
x^2 + 2 --> 3, 6, 11, 18
Step-by-step explanation:
Let's start with the first equation; 3x^2 + 3
Substitute 1 (the first digit in a sequence) for x.
3(1^2) + 3
3(1) + 3
3 + 3 = <u>6</u>
3(2^2) + 3 Then the second digit.
3(4) + 3
12 + 3 = <u>15</u>
Since the two numbers we have so far are 6 and 15, there is only one sequence this could match. 6, 15, 30, 51.
2(1^2) - 1
2(1) - 1
2 - 1 = <u>1</u>
This equation represents 1, 7, 17, 31.
These same steps apply to the other equation as well.
1^2 + 2, then 2^2 + 2, then 2^2 + 2, and so on. (But we don't need to do extra work to figure that out.)
