<h3><u><em>I</em></u><u><em>
nitial considerations</em></u></h3>
- <em>radius = 1.8 in</em>
- <em>tall = 6.7 in</em>
- <em>Volume?</em>
<h3><u><em>Resolution</em></u></h3>
<em>Volume = base area x tall</em>
<em>base area = π x (1.8in)²</em>
<em>base area = 10.179 in²</em>
<em>Volume = 10.179 in² x 6.7 in</em>
<em>Volume = 68.198 in³</em>
<h3 /><h3><em><u>Answer</u></em></h3>
<em>the volume is 68.198 in³</em>
Answer:
See below
Step-by-step explanation:
Solve x-5y=6 for x
First, we need to isolate the x by moving -5y to the other side.
To do this, we need to add 5y to both sides
x - 5y= 6
+5y +5y
x= 5y+6
So, your third answer is correct
R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²
