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nevsk [136]
2 years ago
6

Simplify the following expression (x^0 y^2/3 z^-2)^3/2 divided by (x^2z^1/2)^-6

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
6 0

\dfrac{\left(x^0 y^{\tfrac 23} z^{-2} \right)^{\tfrac 32}}{\left(x^2 z^{\tfrac 12} \right)^{-6}}\\\\\\=\dfrac{1\cdot \left( y^{\tfrac 23}\right)^{\tfrac 32} \cdot \left(z^{-2} \right)^{\tfrac 32}}{\left(x^2 \right)^{-6} \cdot \left( z^{\tfrac 12} \right)^{-6}}~~~~~~~~~~~~~~~~~~;\left[(ab)^m = a^m b^m\right]\\\\\\=\dfrac{y^{1} \cdot z^{-3}}{x^{-12} \cdot z^{-3}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[(a^m)^n = a^{mn}\right]\\\\\\=\dfrac{y}{x^{-12}}\\\\\\

=\dfrac{y}{\tfrac 1{x^{12}}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m} } \right]\\\\\\=yx^{12}

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<em><u>Solution:</u></em>

Given that we have to find the solution of given expression

Given expression is:

1\frac{5}{7} \times 2\frac{3}{4}

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Therefore,

1\frac{5}{7} = \frac{1 \times 7+5}{5} = \frac{12}{5}

2\frac{3}{4} = \frac{2 \times 4+3}{4}=\frac{11}{4}

Now the expression becomes,

1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4}

Solve and simplify the above expression

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In decimal form we get,

\frac{33}{7}=4.714

Thus the solution to given expression is found

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