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lesantik [10]
2 years ago
5

Write six and seven hundred one-thousandths in standard form.

Mathematics
1 answer:
padilas [110]2 years ago
8 0
If i read that correctly, the answer should be 6.372 in standard form
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Write a function rule to describe this statement-
FinnZ [79.3K]

Answer:

let the size of the real item be x

then the size of model as prodived will be =

60% of X

60/100 × X

=3X/5 .

6 0
3 years ago
Help, Help, Please
Lesechka [4]

Answer:

θ = \frac{\pi }{3} (60° )

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Given

cos²θ - sin²θ = 2 - 5cosθ

cos²θ - (1 - cos²θ) = 2 - 5cosθ

cos²θ - 1 + cos²θ = 2 - 5cosθ

2cos²θ - 1 = 2 - 5cosθ ( subtract 2 - 5cosθ from both sides )

2cos²θ + 5cosθ - 3 = 0 ← in standard form

(cosθ + 3)(2cosθ - 1) = 0 ← in factored form

Equate each factor to zero and solve for θ

cosθ + 3 = 0

cosθ = - 3 ← not possible as - 1 ≤ cosθ  ≤ 1

2cosθ - 1 = 0

cosθ = \frac{1}{2} , so

θ = cos^{-1} (\frac{1}{2} ) = \frac{\pi }{3} ( or 60° )

8 0
3 years ago
Read 2 more answers
Simplify the expression to a+bi form: (10+10i)+(-7+3i)
Greeley [361]

Answer:

3+13i

Step-by-step explanation:

(10+10i)+(-7+3i)

Combine the real parts

10+-7 = 3

And the imaginary parts

10i +3i = 13i

Combine them to make the complex number

3+13i

3 0
3 years ago
Solve for y<br> 13.5<br> 12<br> 9<br> 10.5
mariarad [96]
The answer is 9 because I did the math
7 0
2 years ago
Read 2 more answers
Suppose your average, after taking 4 quizzes, is 73(out of 100). What must your average be on the next 5 quizzes to increase you
pychu [463]

x = average of next 5 quizzes

4 * 73 = first 4 quizzes

There will be a total of 4 +5 = 9 quizzes

Average of all quizzes = 88 = (4*73+5x)/9

 

9*88 = 9*(292 +5x)/9

792 = 292 + 5x

500 = 5x

X = 500/5 = 100

<span> Next 5 quizzes need to average 100</span>


8 0
3 years ago
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