Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)
No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.
Answer:
x = 3
Step-by-step explanation:
10x + 1 = 12x - 5
Subtract 1 from each side
10x = 12x - 6
Subtract 12x from each side
-2x = -6
Divided by -2
x = 3
Answer:
Option B, 8 / 6
Step-by-step explanation:
Tangent = Opposite / Adjacent
Tangent of ∠A = Opposite / Adjacent
Tan(A) = 8 / 6 which is the same as Option B
Hope this helps!
What rectangles?
attach a link or pic