Question

Jon caught four fish that weighed a total of 252 pounds.The kingfish weighed twice as much as the amberjack and the white marlin weighed twice as much as the kingfish.The weight of the tarpon was 5 times the weight of the amberjack.How much did each fish weigh?

Answer 1

1 Amberjack 
Kingfish equals 2 Amberjacks
Marlin equals 2 Kingfish or 4 Amberjacks
Tarpon equals 5 AmberJacks

So:
1A plus 2A plus 4A plus 5A equals the 252.
(where A is weight of the AmberJack).

Therefore:
12A equals 252, and A is 21. (252/12 = 21)

Then:
The Amberjack is 21Ibs.
The Kingfish (twice as much as A) is 42Ibs.
The Marlin (four times A) is 84Ibs.
And the Tarpon (five times A) is 105Ibs. 

To Check:
21 + 42 + 84 + 105 = 252

Answer 2

Answer:

The kingfish weighed 72 pounds, the amberjack weighed 36 pounds, the white marline weighed 144 pounds and the tarpon weighed 180 pounds.

Step-by-step explanation:

The following fish were caught:

Kingfish, amberjack and white marlin

Let a=pounds of kingfish, b=pounds of amberjack and c=pounds of white marlin and let d=pounds of tarpin

From the information we know that a=2*b, c=2*a, d=5*b

Let y= the total weighed fish = a+b+c = 252  

Therefore we can write y in terms of a:

$y=252=a+a/2+2*a$

we can solve a which is:

$a=252/3.5=72$

we can solve b as $b=a/2=72/2=36$ and therefore $c=2*a=72*2=144$ and $d=5*b=5*36=180$

So then y= a+b+c =  72+36+144 = 252 pounds of fish

The kingfish weighed 72 pounds, the amberjack weighed 36 pounds, the white marline weighed 144 pounds and the tarpon weighed 180 pounds.