For problems like these, we use something called a ceiling function, in which 
. If we do 
, we get that we do 
, which is 14 buses. We take the ceiling of the division because if we don't, we know that there are going to be extra kids left over that won't be able to seat on a bus. If we just rounded down to 13 buses, we would have been able to seat only 936 kids, a full 64 kids left over.
Radio direction finders are placed at points A and B, which are 4.44 mi apart on an east-west line, with A west of B. The tran
1 answer:
Answer:
3.09 miles
Step-by-step explanation:
Given one distance and two angles, we will need to use the Law of Sines. For this, we need to know the internal angles of the triangle formed by the various bearing lines.
The angle between the bearings of A and B from the transmitter will be the difference of the reverse of the given bearings.
A from T = 39.3° +180° = 219.3°
B from T = 313.9° -180° = 133.9°
Then the angle at T between receivers is ...
219.3° -133.9° = 85.4°
The angle between A and T as measured at B will be ...
313.9° -270° = 43.9°
These angles and length AB can be used with the Law of Sines to find AT:
AT/sin(B) = AB/sin(T)
AT = AB(sin(B)/sin(T)) = (4.44 mi)·sin(43.9°)/sin(85.4°)
AT ≈ 3.09 mi
The distance of the transmitter from A is about 3.09 miles.
You might be interested in