Answer:
if you are solving for o it is −x2−11x−6
6x2
if you are solving for x it is im not sure sorry
Step-by-step explanation:
−9x=x2+x−4x2+x+4x2−x+6ox2+x+6
Step 1: Flip the equation.
6ox2+x2+2x+6=−9x
Step 2: Add -x^2 to both sides.
6ox2+x2+2x+6+−x2=−9x+−x2
6ox2+2x+6=−x2−9x
Step 3: Add -2x to both sides.
6ox2+2x+6+−2x=−x2−9x+−2x
6ox2+6=−x2−11x
Step 4: Add -6 to both sides.
6ox2+6+−6=−x2−11x+−6
6ox2=−x2−11x−6
Step 5: Divide both sides by 6x^2.
6ox2 −x2−11x−6
6x2 6x2
Answer:
o= −x2−11x−6
6x2
Answer:
-2187.15
Step-by-step explanation:
3 x 7/4 - 203 x 54/5
21/4 - 10962/5
5.25 - 2192.4
-2187.15
Answer:
x^2-6x+y^2+4y=-4
Step-by-step explanation:
I am assuming you want the equation of the circle. We know that the equation of a circle is (x-h)^2 + (y-k)^2 =r^2, where r is the radius, and h and k are the x and y coordinates of the center respectively. We can solve for this by plugging in the numbers.
(x-3)^2+(y+2)^2=3^2
x^2-6x+9+y^2+4y+4=9
x^2-6x+y^2+4y=-4
Answer:
- 3 feet is the start point
Step-by-step explanation:
<u>Function given:</u>
- h(t) = −4.5t2 + 19.6t + 3
At t =0 we get h(0) = 3. This is called y-intercept
It is the start point indicating the disc was thrown at 3 feet height