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Vedmedyk [2.9K]
2 years ago
15

Radio direction finders are placed at points A and​ B, which are 4.44 mi apart on an east-west ​line, with A west of B. The tran

smitter has bearings 39.3 degrees from A and 313.9 degrees from B. Find the distance from A.
Mathematics
1 answer:
Scilla [17]2 years ago
6 0

Answer:

  3.09 miles

Step-by-step explanation:

Given one distance and two angles, we will need to use the Law of Sines. For this, we need to know the internal angles of the triangle formed by the various bearing lines.

The angle between the bearings of A and B from the transmitter will be the difference of the reverse of the given bearings.

  A from T = 39.3° +180° = 219.3°

  B from T = 313.9° -180° = 133.9°

Then the angle at T between receivers is ...

  219.3° -133.9° = 85.4°

The angle between A and T as measured at B will be ...

  313.9° -270° = 43.9°

These angles and length AB can be used with the Law of Sines to find AT:

  AT/sin(B) = AB/sin(T)

  AT = AB(sin(B)/sin(T)) = (4.44 mi)·sin(43.9°)/sin(85.4°)

  AT ≈ 3.09 mi

The distance of the transmitter from A is about 3.09 miles.

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Answer:

if you are solving for o it is −x2−11x−6

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Step-by-step explanation:

−9x=x2+x−4x2+x+4x2−x+6ox2+x+6

Step 1: Flip the equation.

6ox2+x2+2x+6=−9x

Step 2: Add -x^2 to both sides.

6ox2+x2+2x+6+−x2=−9x+−x2

6ox2+2x+6=−x2−9x

Step 3: Add -2x to both sides.

6ox2+2x+6+−2x=−x2−9x+−2x

6ox2+6=−x2−11x

Step 4: Add -6 to both sides.

6ox2+6+−6=−x2−11x+−6

6ox2=−x2−11x−6

Step 5: Divide both sides by 6x^2.

6ox2                −x2−11x−6

6x2                      6x2

Answer:

o= −x2−11x−6

          6x2

       

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