Luis could make 0, 1, 2 or 3 touchdowns. We know that in the past he
made 0 touchdowns 4 times, 1 touchdown 7 times, 2 touchdowns 9 times and 3 touchdowns 6 times. To make a probability distribution table, add up 4, 7, 9 and 6; the sum is 26. Thus, based upon past experience, the probability of his making 0 touchdowns is 4/26, of 1 touchdown 7/26, of 2 touchdowns, 9/26 and of 3 touchdowns 6/26: {0.154, 0.269, 0.346, 0.231}. Important: Note that these four decimal probabilities add up to 1, as they must.
The empirical probability of Luis' scoring 2 touchdowns is 0.346.
To find the probability of his scoring more than 1 touchdown, add together the probabilities of his scoring 2 and 3 touchdowns: 0.346+0.231 = 0.577.
The expected value can be calculated as follows:
0(0.154) + 1(0.269) + 2(0.346) + 3(0.231). Note that each term in this expression comes from {0, 1, 2, 3}, and that the fractions all represent the probabilities of each of these four possible outcomes.
The sum is 1.65. This is the "expected value" of the number of touchdowns Luis will likely make. 1.65 is obviously more than 0 or 1 touchdowns, but less than 3 or 4 touchdowns.
Answer:
√1762
Step-by-step explanation:
Square root of 1762
How?
Well 41^2+9^2=c^2
1681+81=c^2
1762=c^2
c=√1762
Answer:
The correct option in both cases is None of these
Step-by-step explanation:
(1.5x , 1.5y)
means we had (x,y) before
we only had to multiply each of the two by 1.5
So the percentage enlargement will be;
(1.5x-x)/x * 100
= 0.5x/x * 100
= 0.5 * 100 = 50%
The answer is none of these
for the second one, we have
(0.7x-x)/x * 100%
= -0.3x/x * 100%
= -30%
This is a 30% reduction
The answer here too is none of these
<h2>Steps:</h2>
(Let x = greater number and y = lesser number)
So this question is asking us for a system of equations. Using the info they provide, we can form these two equations:
So for this, we will be using the substitution method. Since we know that x = y + 7, substitute x with (y + 7) in the second equation as such:
From here we can solve for y. Firstly, distribute 3 so that it multiplies with y and 7:
Next, subtract 3y on both sides of the equation:
Lastly, subtract 5 on both sides of the equation:
Now that we know the value of y, we can substitute it into either equation to solve for x:
<h2>Answer:</h2>
<u>In short, 16 is the lesser number and 23 is the greater number.</u>
