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lozanna [386]
3 years ago
5

In ΔEFG, the measure of ∠G=90°, the measure of ∠F=53°, and GE = 7.9 feet. Find the length of FG to the nearest tenth of a foot.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

FG ≈ 6.0 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan53° = \frac{opposite}{adjacent} = \frac{GE}{FG} = \frac{7.9}{FG}

Multiply both sides by FG

FG × tan53° = 7.9 ( divide both sides by tan53° )

FG = \frac{7.9}{tan53} ≈ 6.0 ft

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