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3 years ago

3x to the x power plus 1 equals 9

Mathematics

1 answer:

Pani-rosa [81]3 years ago

5 0

Do you want the answer or it written out? The written out would be down below and the answer is also down below in the x to the power of x equals 8/3 and its written out.

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Find the value of x. 16 40° D (Round to the nearest tenth as needed.)

dsp73

Answer:

Step-by-step explanation:

3 0

3 years ago

(4y 2 – 5y) + (3y – 7y 2) – (2y 2 + 6y – 5) Simplify.

Elan Coil [88]

Equation at the end of step 1 : (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5) Step 2 :Equation at the end of step 2 : (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5) Step 3 :Equation at the end of step 3 : ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5) Step 4 : Step 5 :Pulling out like terms :

5.1 Pull out like factors :

 -5y2 - 8y + 5 = -1 • (5y2 + 8y - 5)

I hope tht help

4 0

3 years ago

8/2(2+2)= A. 16 B. 1 C. 0 D. 10

s2008m [1.1K]

The answer to this problem is 16.

To solve we must follow the order of operations.

8/2 is 4.

2+2 is 4.

So, now we multiply 4(4) and will get 16 as the answer

So, 16 is the answer.

4 0

3 years ago

How much money is saved on an $80 coat that has been reduced 30%. If you could show me how this is done I would be super gratefu

pentagon [3]

You would get 24$ off of it

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3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago