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2 years ago

What is the equation 8x-3y=6-4x in Stanford form?

Mathematics

1 answer:

IgorLugansk [536]2 years ago

5 0

Answer:

$12x - 3y = 6$

Step-by-step explanation:

Standard form is written this way: $Ax+By=C$

However, in this case, we just have to simplify 8x-3y=6-4x, as it is already mostly in standard form.

So, to do this, we have to combine like terms.

The only like terms that can be combined are -4x and 8x.

So, we add 4x to both sides, and we get: $12x - 3y = 6$ .

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Which graph shows the solutions to x^2+3x-1 ≥ 0

spayn [35]

Answer:

if i'm not mistaken the answer is B

6 0

2 years ago

Read 2 more answers

How do I answer this?

Stels [109]

If you are trying to find the area the answer would be 48

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2 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago

For to 30-60-90 triangle below, the length of side AB is 52 cm.

Jlenok [28]

Answer:

Using 60°

Let side CB be x

Cos60= x/52

Cross multiply=

x= 52cos60

x= 26 cm

7 0

3 years ago

Plz help , due in 5 mins

Grace [21]

Answer:

option a) 30 : 19

Step-by-step explanation:

$Length = 7 \frac{1}{2} = \frac{15}{2}\\\\Width = 4\frac{3}{4} = \frac{19}{4}$

Ratio of length to width:

$\frac{15}{2} : \frac{19}{4}$

$=\frac{\frac{15}{2}}{\frac{19}{4}}\\\\=\frac{15}{2 } \times \frac{4}{19}\\\\=15\times \frac{2}{19}\\\\=\frac{30}{19}\\\\30 : 19$

3 0

2 years ago