Solve attachment EASY POINTS

It takes 16 sections of carpet to cover 1 classroom floor. Tyler wants to know how many sections of carpet are needed for 6 clas

katovenus [111]

If 1 classroom uses 16 sections, then 6 classrooms would use :
6 * 16 = 96 sections

and 14 classrooms would use : 14 * 16 = 224 sections

4 0

4 years ago

What expression is equivalent (2 ½ x 2 ¾)²

Alborosie

2.5x2.75
= 6.875
6.875^2=47.27

3 0

4 years ago

What is transferred by a water wave ?

Greeley [361]

I believe it is C I hope this helped.

7 0

4 years ago

Read 2 more answers

PLEASE HELP!! what is the equation for the parabolic function that goes through the points (-3, 67) (-1, 1) and has a stretch fa

barxatty [35]

Answer:

$f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}$

Step-by-step explanation:

So, we need to find the equation of a parabolic function that goes through the points (-3,67) and (-1,1) and has a stretch factor of 9.

In other words, we want to find a quadratic with a vertical stretch of 9 that goes through the points (-3,67) and (-1,1).

To do so, we first need to write some equations. Let's use the vertex form of the quadratic equation. The vertex form is:

$f(x)=a(x-h)^2+k$

Where a is the leading coefficient and (h,k) is the vertex.

Since a is the leading coefficient, it's also our stretch factor. Thus, let a equal 9.

Also, we have two points. We can interpret them as functions. In other words, (-3,67) means that f(-3) equals 67 and (-1,1) means that f(-1) equals 1. Write the two equations:

$f(x)=a(x-h)^2+k\\f(-3)=67=9((-3)-h)^2+k$

And:

$f(x)=a(x-h)^2+k\\f(-1)=1=9((-1)-h)^2+k$

Now, we essentially have a system of equations. Thus, to find the original equation, we just need to solve for the vertex. To do so, first isolate the k term in the second equation:

$1=9(-1-h)^2+k\\k=1-9(-1-h)^2$

Now, substitute this value to the first equation:

$67=9(-3-h)^2+k\\67=9(-3-h)^2+(1-9(-1-h)^2)$

And now, we just have to simplify.

First, from each of the square, factor out a negative 1:

$67=9((-1)(h+3))^2+(1-9(((-1)(h+1))^2)$

Power of a product property:

$67=9((-1)^2(h+3)^2)+(1-9((-1)^2(h+1)^2))$

The square of -1 is positive 1. Thus, we can ignore them:

$67=9(h+3)^2+(1-9(h+1)^2)$

Square them. Use the trinomial pattern:

$67=9(h^2+6h+9)+(1-9(h^2+2h+1))$

Distribute:

$67=(9h^2+54h+81)+(1-9h^2-18h-9)$

Combine like terms:

$67=(9h^2-9h^2)+(54h-18h)+(81+1-9)$

The first set cancels. Simplify the second and third:

$67=36h+73$

Subtract 73 from both sides. The right cancels:

$67-73=36h+73-73\\36h=-6$

Divide both sides by 36:

$(36h)/36=(-6)/36\\h=-1/6$

Therefore, h is -1/6.

Now, plug this back into the equation we isolated to solve for k:

$k=1-9(-1-h)^2$

First, remove the negative by simplifying:

$k=1-9((-1)(h+1))^2\\k=1-9((-1)^2(h+1)^2)\\k=1-9(h+1)^2$

Plug in -1/6 for h:

$k=1-9(-\frac{1}{6}+1)^2$

Add. Make 1 into 6/6:

$k=1-9(-\frac{1}{6}+\frac{6}{6})^2\\ k=1-9(\frac{5}{6})^2$

Square:

$k=1-9(\frac{25}{36})$

Multiply. Note that 36 is 9 times 4:

$k=1-9(\frac{25}{9\cdot4})\\ k=1-\frac{25}{4}$

Convert 1 into 4/4 and subtract:

$k=\frac{4}{4}-\frac{25}{4}\\ k=-\frac{21}{4}$

So, the vertex is (-1/6, -21/4).

Now, plug everything back into the very original equation with 9 as a:

$f(x)=a(x-h)^2+k\\f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}$

And this is our answer :)

8 0

3 years ago

Read 2 more answers

Suppose Wal-Mart stock is selling at $59 a share and Mattel stock is selling at $28 a share. Amy has a maximum of $6000 to inves

Ulleksa [173]

Answer:

88 shares of Wall-Mart stock,

a) Step-by-step explanation, 22 shares of Mattel stock. b) $192

Given:

Suppose Wall-Mart stock is selling at $59 a share and Mattel stock is selling at $28 a share.

Amy has a maximum of $6000 to invest.

She wishes to purchase four times as many shares of Wall-Mart as of Mattel.

Only whole shares of stock can be purchased.

Question asked:

a) How many shares of each will she purchase?

b) How much money will be left over?

Solution:

Selling price of each share of Wall-Mart stock = $59

Selling price of each share of Mattel stock = $28

Let number of shares of Mattel stock purchased = $x$

Then, number of shares of Wall-Mart stock = $4x$

Total money invested =$6000

Shares of Mattel stock $\times$ $28 + Shares of Wall-Mart stock $\times$ $59 = $6000

$28\times x+59\times4x=6000\\28x+236x=6000\\264x=6000$

Dividing both sides by 264

$x=22\frac{192}{264}$

That means, total 22 shares of Mattel stock is purchased and 192 is the money left over:-

Number of shares of Wall-Mart stock = $4x$ = $4\times22=88$

Total amount spent on Mattel stock shares = 22 $\times$ $28 = $616

Total amount spent on Wall-mart stock shares = 88 $\times$ $59 = $5192

Total amount spent on both shares = $616 + $5192 = $5808

Money left over = $6000 - $5808 = $192

a) He will purchase 88 shares of Wall-Mart stock and 22 shares of Mattel stock.

b) Money left over is $192.

6 0

4 years ago