The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be
<h3>How to calculate the values?</h3>
The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be:
= (1520 - 1232)/1232
= 288/1232
= 0.234
The relative unfairness of an apportionment that gives a new board member to salinas rather than to Joshua will be:
= (1448 - 1333)/1333
= 115/1333
= 0.086
The regional governing board that should receive the new board member is Salinas.
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Positive: 690
Negative: -30
Answer:
It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0
Explanation:
We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:
Let's start with the roots:
x=3, x=−4
So let's move the constants over with the x terms to have equations equal to 0:
x−3=0, x+4=0
Now we can set up the equation, as:
(x−3)(x+4)=0
We can now distribute out the 2 quantities:
x2+x−12=0
The answer is 7/5 th. You can add fractions without first having a common denominator so you would change the 8's by multiplying it by 5 to get 40 and you would multiply the 5 by 8 to get 40 as well. And the rule whatever you do to the bottom you have to do to the top so whatever you multiplied 8 by do the same for the numerator and whatever you multiplied 5 by you do the same for the numerator. So your new equation would be (75/40+16/40)+(-35/40). you would then add the numerator's across to get 56 and the denominator would stay the same so the answer is 56/40. But you have to now simplify 56/40 down to 14/10 and then once more to 7/5 which is the final answer.
