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2 years ago

Evaluate (3)^1/6 × (3)^-2/3

Mathematics

2 answers:

Elan Coil [88]2 years ago

7 0

39918656718818881883

Lelechka [254]2 years ago

3 0

Answer:

$\dfrac{1}{\sqrt{3}}$

Step-by-step explanation:

Evaluate: $3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}$

Apply exponent rule: $a^b \times a^c=a^{b+c}$

$\begin{aligned} \implies 3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}&=3^{\frac{1}{6}-\frac{2}{3}}\\ &=3^{-\frac{1}{2}\end{aligned}$

Apply exponent rule: $a^{-n}=\dfrac{1}{a^n}$

$\implies 3^{-\frac{1}{2}}=\dfrac{1}{3^{\frac{1}{2}}}=\dfrac{1}{\sqrt{3}}$

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pipe A is a inlet pipe filling the tank at 8000l/hr and pipe B is the outlet pipe which empties the tank in 3 hours.the capacity

lawyer [7]

Well , in 3 hours , the amount of the tank that will be filled with pipe A = 8,000 x 3 = 24,000 L

Pipe could empty that 24,000 L in 3 hours.

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3 years ago

What is the answer for 5-2+7x6-2?

sergiy2304 [10]

Answer: 43

Step-by-step explanation:

5-2+7x6-2

3+42-2

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3 years ago

1. When Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nicke

vaieri [72.5K]

1- The total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- There is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

1- Given that when Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nickels was twice the number of dimes, to determine, if there were 50 nickels, what was the total value of the Lucas coins dumped out of his piggy bank, the following calculation must be performed:

Nickel = 0.05
Dime = 0.10
N + D = X
N + 1 / 2N = X
50 + 25 = 75
50 x 0.05 + 25 x 0.1 = X
2.50 + 2.50 = X
5 = X

Therefore, the total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Since when Franco dumped the coins out of his piggy bank, he noticed that there were only nickels and quarters, and the number of quarters was six more than half the number of nickels, to determine, if the total value of the coins Franco and Lucas dumped out of each piggy bank was the same, how many coins did Franco dump out of his piggy bank, the following calculation must be performed:

Nickel = 0.05
Quarter = 0.25
Q = 2N + 6
4 x 0.25 + 6 x 0.25 = 1 + 1.5 = 2.5
8 x 0.05 = 0.40
2.5 + 0.4 = 2.9
8 x 0.25 + 6 x 0.25 = 2 + 1.5 = 3.5
16 x 0.05 = 0.8
3.5 + 0.8 = 4.3
10 x 0.25 + 6 x 0.25 = 2.5 + 1.5 = 4
20 x 0.05 = 1
4 + 1 = 5
10 + 6 + 20 = 36

Therefore, Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- Since when Callie dumped the coins out of her piggy bank, she noticed that there were only nickels, dimes and quarters, and the number of dimes was one more than twice the number of quarters, and there were half as many quarters as nickels, y the coins dumped out of Callie's piggy bank had a total value equal to that of the coins dumped out of Franco's and Lucas' piggy banks combined, to determine what was the total value of the nickels and dimes dumped out of Callie's piggy bank, the following calculation should be performed:

Nickel = 0.05
Dime = 0.10
Quarter = 0.25
(D + 1) + 1 / 2Q + N = 10
1 x 0.1 + 20 x 0.1 + 10 x 0.25 + 20 x 0.05 = 2.1 + 2.5 + 1 = 5.6
1 x 0.1 + 36 x 0.1 + 18 x 0.25 + 36 x 0.05 = 3.6 + 4.5 + 1.8 = 9.9
1 x 0.1 + 38 x 0.1 + 19 x 0.25 + 38 x 0.05 = 3.9 + 4.75 + 1.9 = 10.55

Therefore, there is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

Learn more in brainly.com/question/11096797

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3 years ago

The points scored on a test for a sample of

jasenka [17]

Answer:

The mean is 42.6

Step-by-step explanation:

$6+90+16+80+15 + 70 + 4 + 60 = 341 \\ there \: are \: 8 \: numbers \: in \: total \: so \: you \: divide \: the \: sum \\ by \: 8. \\ 341 \div 8 = 42.625 \\ mean≈42.6$

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3 years ago

Picture says all 20 charecters needed

Alika [10]

Answers:

Lower bound = 41.3

Upper bound = 41.5

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Explanation:

49.15 is the smallest f can be while 49.24 is the largest it can be. Well technically we could have something like 49.2499 or 49.24999 and so on. We slowly approach 49.25 but never actually get there

So the variable f is between 49.15 and 49.25 inclusive of the first value but excluding the second value. We can write it as $49.15 \le f < 49.25$

For similar reasoning, $7.75 \le g < 7.85$

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If we wanted to subtract those variables and get the smallest result possible, then we need to pick values that are closest together. It might help to set up a number line.

This means we'd go for f = 49.15 and g = 7.85

The lower bound for f-g is f-g = 49.15-7.85 = 41.3

In contrast, the upper bound is when the two variables are spaced as far apart as possible. The upper bound is f-g = 49.25 - 7.75 = 41.5

7 0

2 years ago

Read 2 more answers