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Lana71 [14]
1 year ago
7

Evaluate (3)^1/6 × (3)^-2/3

Mathematics
2 answers:
Elan Coil [88]1 year ago
7 0
39918656718818881883
Lelechka [254]1 year ago
3 0

Answer:

\dfrac{1}{\sqrt{3}}

Step-by-step explanation:

Evaluate:  3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}

Apply exponent rule:  a^b \times a^c=a^{b+c}

\begin{aligned} \implies 3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}&=3^{\frac{1}{6}-\frac{2}{3}}\\ &=3^{-\frac{1}{2}\end{aligned}

Apply exponent rule:  a^{-n}=\dfrac{1}{a^n}

\implies 3^{-\frac{1}{2}}=\dfrac{1}{3^{\frac{1}{2}}}=\dfrac{1}{\sqrt{3}}

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tamaranim1 [39]
-2a+2=22

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Step-by-step explanation:

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3 years ago
Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s
nignag [31]

Answer:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

Step-by-step explanation:

Given

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Required

Solve

We have:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Collect like terms

1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t  + 8

1.3t^3 + t^2 -42t  + 8

So:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

8 0
2 years ago
How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
Two thirds of 12 minus d
fenix001 [56]

Step-by-step explanation:

2 /3 of 12 - d

2/3 * 12 - d

8 - d

7 0
2 years ago
Read 2 more answers
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