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Lana71 [14]
2 years ago
7

Evaluate (3)^1/6 × (3)^-2/3

Mathematics
2 answers:
Elan Coil [88]2 years ago
7 0
39918656718818881883
Lelechka [254]2 years ago
3 0

Answer:

\dfrac{1}{\sqrt{3}}

Step-by-step explanation:

Evaluate:  3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}

Apply exponent rule:  a^b \times a^c=a^{b+c}

\begin{aligned} \implies 3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}&=3^{\frac{1}{6}-\frac{2}{3}}\\ &=3^{-\frac{1}{2}\end{aligned}

Apply exponent rule:  a^{-n}=\dfrac{1}{a^n}

\implies 3^{-\frac{1}{2}}=\dfrac{1}{3^{\frac{1}{2}}}=\dfrac{1}{\sqrt{3}}

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Astronomers sometimes use angle measures divided into degrees, minutes, and seconds. One degree is equal to 60 minutes, and one
Fynjy0 [20]

Answer:

Here's what you need to know to answer this question:

            If two angles are "complementary"

            then they add up to 90 degrees.

So now you know that

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The thing that makes it tough is subtracting some minutes

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How you do that is:  An unusual kind of regrouping ('borrowing').

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This time, when you take '1' from a place, it gives you '60'

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-- Take 1 degree away from the 90 degrees.

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   then you have                    89 degrees  59 minutes  60 seconds .

Now the subtraction is a lot easier.

            89 degrees  59 minutes  60 seconds

minus   48 degrees  26 minutes    8 seconds .

That's easy to do, and the difference is the measure of Angle-K.

Step-by-step explanation:

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