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IRISSAK [1]
3 years ago
15

Which number line represents the solution set for the inequality 4(x + 3) 5 2 2X?

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

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Can anyone help me with this. please​
zvonat [6]

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2+b^2=c^2

7^2+KL^2=25^2

49+KL^2=625

KL^2=625-49

KL=\sqrt{576

KL=24

take M as reference angle

using tan rule

tan M=/opposite/adjacent

tan M=KL/ML

tan M=24/7

5 0
3 years ago
Find the ratio of ruppees 5 to 50 paise​
Inga [223]
5:50 —> divide by 5 so it becomes 1:10
: means to
7 0
2 years ago
Select the correct answer​
White raven [17]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
6 times 9+6+9 =? <br>Pls help
Nata [24]

144

If you add 9+6+9 is will give you 24 than you would times that by 6. So 9+6+9= 24 next 24×6=144.

6 0
3 years ago
Read 2 more answers
A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,
tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0
3 years ago
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