Answer:
(-2,1)
Step-by-step explanation:
So we are given f(-3)=1 since the point (-3,1) is on f(x).
We want to use this point to find a point on f(x-1).
Now,
f(-3)=1
and we want
f(x-1)=1
What would x need to be such that x-1 is -3.
x-1=-3
Add 1 on both sides:
x=-3+1
x=-2
x would need to be -2 in f(x-1)=1 in order to use that f(-3)=1.
So (-2,1) is the point for the function f(x-1) that corresponds to the point (-3,1) for f(x).
I know that f(x-1) would only be effecting our input because x-1 is the input.
Yes im here ask away. I am doing calculus right now
Cross multiply. Distribute...
OH GOD IT'S A QUADRATIC
<em>(our equation is in ax² + bx + c = 0 form. a=3. b= -38. c= -8.
</em><em>plug these values into the quadratic formula and simplify.)</em>
Approximate values for x: -0.20714 or 12.874
Shop B. This is cause shop A charges about $1.25 for each g of peanut butter, while Shop B charges only $1.20 for each g of peanut butter. Hope this helps!
I believe the answer is 3.
If you would like me to show my work please reply saying so.
Sorry if I'm wrong, but I hope this helps.
4(3x - 6) +15 = 27
Distributive Property
12x + -24 + 15 = 27
Add the two constants (numbers without variables)
12x + -9 = 27
Because 9 is negative, add 9 to both sides.
12x = 36
Divide both sides by the coefficient (number with x)
x = 3
