Find the midpoint of the segment with the following endpoints. (-4, 5) and (-1, 1)

Mathematics

1 answer:

Solnce55 [7]3 years ago

6 0

Answer:

(-5/2 , 2)

Step-by-step explanation:

add the two x coordinates of the endpoints and divide by 2. Do the same for the y coordinates.

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Round 299 to the nearest hundred. Enter your answer in the box below.

Troyanec [42]

Answer:

300

Step-by-step explanation:

hundreds tens ones

2 9 9

We look at the tens

It is 5 or higher so we round up the hundreds place

2 becomes 3

300

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3 years ago

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Find the inverse g(x)=x/5-6

STALIN [3.7K]

Interpreted: $g(x) = \frac{x}{5} - 6$
Let $y = g(x)$
$y = \frac{x}{5} - 6$
$x = \frac{y}{5} - 6$ (Interchange the x and y-values)

$\frac{y}{5} = x + 6$ (Solve for y)
$y = 5(x + 6)$

$\therefore g^{-1}(x) = 5(x + 6)$

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3 years ago

Mary and Julie both have a goal of raising $1000 for

zalisa [80]

Answer:

julie

Step-by-step explanation:

12 x 4 +=48

19x 6 = 114

8 0

2 years ago

A parabolà can be drawn given a focus of (7,9) and a

NeTakaya

from the provided focus point and directrix, we can see that the focus point is above the directrix, meaning is a vertical parabola and is opening upwards, thus the squared variable will be the "x".

keeping in mind the vertex is half-way between these two fellows, Check the picture below.

$\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} h = 7\\ k = 7\\ p = 2 \end{cases}\implies 4(2)(y-7)=(x-7)^2\implies 8(y-7)=(x-7)^2 \\\\\\ y-7=\cfrac{1}{8}(x-7)^2\implies \boxed{y=\cfrac{1}{8}(x-7)^2+7}$