All categories

2 years ago

Find the midpoint of the segment with the following endpoints. (-4, 5) and (-1, 1)

Mathematics

1 answer:

Solnce55 [7]2 years ago

6 0

Answer:

(-5/2 , 2)

Step-by-step explanation:

add the two x coordinates of the endpoints and divide by 2. Do the same for the y coordinates.

You might be interested in

Which table represents a linear function?

Natali5045456 [20]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$The \: \: third \: \: table.$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0

3 years ago

Identify the values of a , b , and c in the following quadratic equation.<br><br> 2 x2 + 3 x + 7 = 0

Liula [17]

Depends on where you are in the math book but this would be the most simple way.
n= number
sqar(-1) = i

8 0

3 years ago

Read 2 more answers

The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte

Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

$[(n - 1)\times S^{2} / X^{2} \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2} / X^{2} 1- \alpha/2, n- 1 ]$

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

$X^{2}_{[\alpha/2, n - 1]} = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401$

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0

2 years ago

PLS HELP ONLY 1 question

Vesna [10]

The answer is C. Here you go.

5 0

3 years ago

Solve for x x + 47 = -23

givi [52]

X = -23 - 47
x = -70
-70 + 47 = -23

7 0

3 years ago

Read 2 more answers