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gtnhenbr [62]
3 years ago
5

I NEED HELP OR I FAIL THIS TEST PLEASE

Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer:

C

Step-by-step explanation:

You start with 15 dollars then you can use up to x amount of tickets.

Lilit [14]3 years ago
7 0

Answer: c

Step-by-step explanation:

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Select the property of equality used to arrive aSelect the property of equality used to arrive at the conclusion.
vovikov84 [41]

would it be b

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3 years ago
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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
Please help!!!!!!! I will medal
Damm [24]
The answer to this question is \frac{123}{500}. Hope this helps.
6 0
4 years ago
Solve the equation.<br> d divided by 3 = 139<br> d =<br><br> (Type a whole number.)
wolverine [178]

Answer:

417

Step-by-step explanation:

HOPE THAT HELPED

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3 years ago
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3r+(7+8)/(t-3)when r=4, s=3 and t=5
mars1129 [50]

Answer:

19.5

Step-by-step explanation:

3r+(7+8)/(t-3)

3(4)+(15)/(5-3)

12+(15/2)

12+7.5

19.5

6 0
3 years ago
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