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torisob [31]
3 years ago
7

Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest fo

rm. a1 = – 25 an = an–1–14 an=
Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Given :

a_1=-25 .

a_n=a_{n-1}-14 .

To Find :

The general equation of a_n .

Solution :

We know , when difference between any two consecutive terms in an A.P is equal , then the series is in arithmetic progression .

Now , common difference ,

d=a_n-a_{n-1}\\\\d=-14

Also , first term is -25 .

Now , general term of an A.P is given by :

a_n=a+(n-1)d\\\\a_n=-25+(n-1)(-14)\\\\a_n=-25-14n+14\\\\a_n= -11-14n

Hence , this is the required solution .

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving? -3/4m-1/2=2+1/4m​
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6 0
2 years ago
Find X pleaseee :).
larisa [96]

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22

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(5x-7 )+(4x-11)=180 ( it equals 180 because those two angles equal 180)

Then add the similar things together

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5 0
2 years ago
To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first
Fofino [41]

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x =  265+x

Average score = (Sum of all scores) ÷ (Number of tests)

=\dfrac{265+x}{4}

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

5 0
2 years ago
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