Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer:
0
Step-by-step explanation:
The slope of the line is 0 as it is parallel to x-axis.
Slope = (y2 - y1)/(x2 - x1)
= (2-2)/(4-(-2))
= 0
The rate of change of the linear function represented by the table is 3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
The standard linear equation is in the form:
y = mx + b
Where m is the rate of change and b is the y intercept.
From the table, using the point (0, -7) and (2, -1):
m = [-1 - (-7)] / (2 - 0) = 3
The rate of change of the linear function represented by the table is 3
Find out more on equation at: brainly.com/question/2972832
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Answer:
18=2x
x=9
Step-by-step explanation:
hope it helps bro
5892 divided by 18 is 327 rounded
