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Elina [12.6K]
3 years ago
12

CONVERTING METRIC UNITS - LENGTH WEIGHT & VOLUME 1

Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer:

2 KM 2 L 2 KG I dont know the rest i figured i could help someone but thats all i can do at the moment sorry i might come back to finish it later.

Step-by-step explanation:

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A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is e
aivan3 [116]
To find the volume of the box you will use the volume of the sphere formula to find the radius of the circular region of the sphere. You wil then double the radius to find the diameter.

V = 4/3 x pi x r^3
972 x pi= 4/3 x pi x r^3
729 = r^3
The cubic root of 729 is 9 because 9 x 9 x 9 = 729.

The radius is 9 inches, and the diameter is 18 inches.

The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.
4 0
3 years ago
Which trigonometric functions are negative in the fourth (IV) quadrant?
anzhelika [568]
<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0
3 years ago
Does this table represent a function? Why or why not?
Alina [70]

Answer: the answer is B

Step-by-step explanation:

7 0
3 years ago
A rectangle sandbox has an area of 64 square yards. What might be the perimeter of the sandbox?
zubka84 [21]

Answer:

32

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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