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Step2247 [10]
3 years ago
8

HELP WITH ONE MANY OR NONE SOLUTION PROBLEM

Mathematics
2 answers:
Studentka2010 [4]3 years ago
6 0
18x-15=15x-18
3x-15=-18
3x=-3
x=-1

one solution
alexgriva [62]3 years ago
3 0
There would only be on answer as this is not a quadratic equation.  Please mark Brainliest!!!
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3x

Step-by-step explanation:

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3 0
3 years ago
X2+9x+20 plz help me with it plz​
ICE Princess25 [194]

Answer:

11x + 20

Step-by-step explanation:

x2 + 9x + 20

2x + 9x + 20

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4 0
3 years ago
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What are the a b and c values of 3x^2-4x=20
joja [24]

Answer:

a = 3, b = -4, c = -20

Step-by-step explanation:

<u>Step 1:  Find the a, b, and c values</u>

ax^2 + bx +  c = 0

3x^2 - 4x - 20 = 0

The a value is:  3

The b value is:  -4

The c value is:  -20

Answer:  a = 3, b = -4, c = -20

8 0
3 years ago
A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.21, the probabil
WITCHER [35]

Answer:

2.65 dollars

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x1P(x1) + x2P(x2) + ... + xnP(xn)

Where x1, x2, ... , xn are the possibles values of the variable and P(x1), P(x2), ... , P(xn) are the probabilities of x1, x2, ... , xn respectively.

In this case, the roll can comes up 1, 2, 3 or 4 and you can win 1, 2, 3 or 4 dollars respectively. So, taking into account that they are mutually exclusive events, the probability that the player win 1, 2, 3 or 4 dollars is:

P(1) = 0.21

P(2) = P(1∪2) - P(1) = 0.42 - 0.21 = 0.21

P(3) = P(2∪3) - P(2) = 0.51 - 0.21 = 0.3

P(4) = 1 - P(1) - P(2) - P(3) = 1 - 0.21 - 0.21 - 0.3 = 0.28

Therefore, If you win the amount that appears on the die the expected winning are:

E(x) = $1P(1) + $2P(2) + $3P(3) + $4P(4)

E(x) = $1(0.21) + $2(0.21) + $3(0.3) + $4(0.28)

E(x) = $2.65

4 0
3 years ago
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