All categories

2 years ago

The temperature falls from 0 degrees to – 12.3 degrees in 3.5 hours. Which expression finds the change in temperature

Mathematics

1 answer:

MatroZZZ [7]2 years ago

8 0

Answer:

3.514 degrees per hour

Step-by-step explanation:

To find change per hour, you find the slope, which is change in output (temperature) over change in input (hours)

y2-y1 / x2-x1

-12.3 - 0 / 3.5

3.514 degrees per hour

You might be interested in

If a =c+2 what is the value of c when a=5

nikdorinn [45]

(5)=c+2 Plug in your a value then combine like terms to find c
3=c

3 0

3 years ago

What is the present of 4 out of 30

alisha [4.7K]

The present of 4 out of 30 is 13.33%

The present of 1 out of 30 is 3.33%

The present of 25 out of 30 is 83.33%

<u>Step-by-step explanation:</u>

The percentage is calculated by dividing the required number with the full quantity and multiplied by 100.

First sum :

$(\frac{4}{30} )\times 100=13.33 \%$

Second sum :

$(\frac{1}{30} ) \times 100 = 3.33%$

Third sum:

$(\frac{25}{30} )\times100 = 83.33%$

7 0

3 years ago

Which list contains ONLY rational numbers?

Debora [2.8K]

The answer is C. 1/7, 9, 2 Hoped this helped
Feel free to ask anymore questions at branily.com

3 0

3 years ago

Read 2 more answers

3+8 12 if and only if 5×4 25

Anna11 [10]

Answer:

The symbolic form of the given statement is

p <==> q

7 0

3 years ago

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.3 in/s. At

Angelina_Jolie [31]

Answer:

The volume is changing at a rate given by:

$\frac{dV}{dt} =19559.56\,\,\frac{in^3}{s}$

Step-by-step explanation:

Let's recall the formula for the volume of acone, since it is the rate of the cone changing what we need to answer:

Volume of cone = $\frac{1}{3} B\,*\,H$

where B is the area of the base (a circle of radius R) which equals = $\pi\,R^2$

and where H stands for the cone's height.

We apply the derivative over time operator ( $\frac{d}{dt}$ ) on both sides of the volume equation, making sure that we apply the rule for the derivative of a product:

$V=\frac{1}{3} B\,*\,H\\\\V= \frac{1}{3} \pi\,R^2\,H\\\frac{dV}{dt} =\frac{\pi}{3}\,( \frac{d(R^2)}{dt} H+R^2\,\frac{dH}{dt} )\\\frac{dV}{dt} =\frac{\pi}{3}\,( 2\,R\,\frac{dR}{dt}\, H+R^2\,\frac{dH}{dt} )\\\frac{dV}{dt} =\frac{\pi}{3}\,( 2\,(110\,in)(1.4\,\frac{in}{s} )\,(151\,in)+(110\.in)^2\,(-2.3)\frac{in}{s} )\\\frac{dV}{dt} =19559.56\,\,\frac{in^3}{s}$

8 0

3 years ago