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Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
C.
343 fourths
Step-by-step explanation:
C.
343 fourths
We can re-create the quadratic equation by
(x -3) * (x -2)
x^2 -5x + 6 = 0
Answer:
x= 62
y= 54
Step-by-step explanation:
Step one:
given data
let the numbers be x and y and the larger be x the smaller be y
The difference between two numbers is 8
x-y= 8-----------1
If the larger is subtracted from three times the smaller, the difference is 100
3y-x=100------------2
from eqn 1, x= 8+y
put this in eqn 2
3y-(8+y)=100
3y-8-y=100
collect liker terms
3y-y-8=100
2y=108
y= 54
put y= 54 in eqn 1
x-y=8
x-54= 8
x= 8+54
x=62
