If f(x)= -5-4 and g(x) = -3-2 find (f+g)(x)

A shoe store sold 340 pairs of shoes in one day. The number of pairs f athletic shoes sold was 4 more then twice the number of p

sp2606 [1]

344 pairs of athelic shoes were sold bc when f=688 double 344 bc its individual shoes

if u set up the equation f÷2 - 4 = 340 and u input f u get the answer.....hope this helped

5 0

2 years ago

Sara has 24 sweets

Tresset [83]

<h2>Hello!</h2>

The answer is:

The expression for the number of sweets that Sara and Tim have now, are:

$Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}$

To write the expressions for the number of sweets that Sara and Tim have now, we need to follow the next steps:

Sara starts with 24 sweets and Tim starts with 24 sweets

$Sara=24 Sweets\\Tim=24 Sweets$

Then, Sara gives Tim x Sweets

$Sara=(24-x)Sweets\\Tim=(24+x)Sweets$

Then. Sara eats 7 of her Sweets

$Sara=(24-x-7) Sweets\\Sara=(17-x )Sweets\\Tim=(24+x) Sweets$

Then, Tim eats half of his sweets

$Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}$

So, the expression for the number of sweets that Sara and Tim have now, are:

$Sara=(17-x) Sweets\\\\Tim=\frac{(24+x)Sweets}{2}$

Have a nice day!

8 0

3 years ago

What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?

snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

6 0

3 years ago

Given a+b=7 and a–b=3, find: 2a·2b

nekit [7.7K]

I believe the answer is 40

5 0

2 years ago

A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?

Leya [2.2K]

Ok, so you are given an equation in standard form, 5x+4y=2, and a point, (7, 5). You are being asked to write the equation for a line that is parallel to the equation in standard from, and that includes the point (7, 5).

First, let's start by finding the slope of your new line. We know that it needs to have the same slope as 5x+4y=2, because parallel lines have the same slopes. To do that, we need to put the equation into slope-intercept form (y=mx+b), which means we need to isolate the "y."

5x+4y=2

-5x -5x (subtract 5x from both sides to move it to the right side of your equation)

4y = 2 - 5x

/4 /4 /4 (divide all the terms by 4 to get "y" by itself)

y = (1/2) - (5/4)x ... I suggest leaving your slope as a fraction.

Now, we know that our slope, m , is going to be -(5/4).

Next, we are going to use our slope, -(5/4), and point, (7, 5), to find the b-value (y-intercept) of your new line. Let's plug in what we know:

y = 5

m = -(5/4)

x = 7

y=mx+b

5=(-5/4)(7) + b -> I plugged in what we knew for y, m, and x.

5 = -(35/4) + b -> I multiplied the numbers in the numerator (5 x 7) to get 35/4

20/4 = -(35/4) + b -> I converted 5 into a faction with a denominator of 4 by multiplying by (4/4)

+(35/4) +(35/4) -> I add (35/4) to both sides to isolate b

55/4 = b ... or b = 13.74

Answer:

m = -(5/4)

b = 13.75

7 0

2 years ago