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iogann1982 [59]
2 years ago
11

Helpppppppppppppppppp 25 points

Mathematics
1 answer:
Otrada [13]2 years ago
7 0

\qquad\qquad\huge\underline{\boxed{\sf Answer}}

Things we need to keep in mind in order to plot a point :

  • x - coordinate of the point shows its distance from origin in horizontal direction.

  • y - coordinate of the point shows its distance from origin in vertical direction.

Signs of the coordinates shows which side it lies on.

  • if x coordinate is positive then the point lies on right side of y - axis and if it is negative then it lies on left side of y - axis.

similarly,

  • if y coordinate is positive then the point lies above the x - axis , and if it's negative then it lies on down the x - axis.

Now, let's proceed ~

First check out its x - coordinate on origin and move up or down according to its y - coordinate and you will get your required point.

So, for point (1 , 0) it has y - coordinate = 0, so it lies on x - axis at the x - coordinate of 1.

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No no no it is 2 meters 15 seconds maybe u write not correctly. but according to your choice of answers, only D is suitable here
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3 years ago
Identify the linear term in the function of y = 2x2 − 5x − 12
MakcuM [25]

Answer:

The linear term is -5x

Step-by-step explanation:

The linear term is the term that has the degree equal to 1.

The given function is

y = 2x^2 − 5x − 12

here 2x^2 = quadratic term i.e having degree 2

-5x = linear term i.e having degree 1

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so, The linear term is -5x

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What is the common ratio for the geometric sequence?<br><br> 35/2, 7, 14/5, 28/25, ..…
LiRa [457]

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2/5

Step-by-step explanation:

8 0
3 years ago
If 4 Maths books are selected from 6 different Maths different English books, how many ways can the seven om Maths books and 3 E
alexgriva [62]

Answer:

Please see the answer below

Step-by-step explanation:

a. Since there’s no restrictions .Therefore , the number of ways = 7!*150 = 756000

b. The number of ways such that the 4 math books remain together

The pattern is as follows:  MMMMEEE, EMMMMEE, EEMMMME, and EEEMMMM

Where M = Math’s Book and E= English Book.  

Number of ways = 4!*8!*4*150= 86400 ways.

c. The number of ways such that  math book is at the beginning of the shelf

The number of ways = 6!*4*150 = 432000

d. The number of ways such that  math and English books alternate

The number of ways = 150*4!*3! =2160 ways

e.  The number of ways such that math is at the beginning and an English book is in the middle of the shelf. The number of ways = 4*3*5!*150 =216000 ways.

6 0
4 years ago
What is the answer to this problem
Aleks04 [339]

Answer:

14 cm^2

Step-by-step explanation:

You find the area of both triangles, and subtract by 4

6x3x1/2x2 - 2x2

18 - 4

14

3 0
3 years ago
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