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3 years ago

How do you write 9/2 as a percentage?

Mathematics

2 answers:

olga55 [171]3 years ago

6 0

9/2 would be converted to 450%

Snowcat [4.5K]3 years ago

5 0

The fraction 9/2 can be expressed as 450 percent.

You can find this value by dividing the denominator and multiplying the result by 100%, so:

9/2 in percent = 9 ÷ 2 × 100% = 4.5 × 100% = 450%

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Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The

lys-0071 [83]

Answer:

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

They randomly survey 391 drivers and find that 319 claim to always buckle up.

This means that $n = 391, \pi = \frac{319}{391} = 0.8159$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 - 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.7877$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 + 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.8441$

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

8 0

3 years ago

A wheel spines at a rate of 41 revolutions per minute. how many revolutions per hour does it spin

ch4aika [34]

This is simple math, you know 60 minutes in 1 hour, so do 60 x 41 = 2,460

So it spins 2,460 times per hour.

Hope this helps!

8 0

3 years ago

14. Suppose that 1 out of every 10,000 doctors in a certain region is infected with the SARS virus; in the same region, 20 out o

hram777 [196]

Answer:

The person in the at-risk population is much more likely to actually have the disease

Step-by-step explanation:

The probability of a randomly selected doctor having the disease is 1 in 1,000 (P(I)=0.0001).

The probability that a doctor is infected with SARS, given that they tested positive is:

$P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.0001*0.99}{0.0001*0.99+(1-0.0001)*0.01}\\P(I|+)=9.9*10^{-3}$

The probability of a randomly selected person from the at-risk population having the disease is 20 in 100 (P(I)=0.20).

The probability that a person in the at-risk population is infected with SARS, given that they tested positive is:

$P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.2*0.99}{0.2*0.99+(1-0.2)*0.01}\\P(I|+)=0.962$

Therefore, the person in the at-risk population is much more likely to actually have the disease

3 0

3 years ago

Which two operations are needed to write the expression that represents "eight more than the product of a number and two"?

sp2606 [1]

For this case we must represent the following expression algebraically:

"eight more than the product of a number and two"

Let "x" be the variable that represents the unknown number

We have to:

the product of a number and two is represented as: $2x$

Then, the full expression will be:

$2x + 8$

Thus, we use multiplication and addition.

ANswer:

Option C

3 0

4 years ago

Read 2 more answers

If you multiplied the mystery number by 1000, the resulting number would have a 7 in the ones place.

ser-zykov [4K]

The answer rounded to the nearest hundredth is 84.65.

Consider the number 84.647.

If we multiply this number by 1000, the result is 84647 which has 7 in its one's place.

Also, note that the value of the digit in the ones place is 4, which is half of 8, the value in the tenths place.

The remaining digit in the tenths place is 4.

Hence, the correct answer is 84.65 rounded to the nearest nundredth.

8 0

4 years ago