One way you could do this is by dividing 94 by 3 and then 95 by 4. This gives you the KPH (Kilometers per hour) of both trains. The first speed you mentioned, we will call that speed 'A.' The second one will be speed 'B.' Speed A's KPH is 23.75 MPH. Speed B's KPH is 31.333. We can change these into fractions (23 3/4 and 31 1/3.) These fractions could then be set into like terms. (This gives us 285/12 and 376/12) We then add these together. This gives us 661/12. The next thing to do is to convert this back to a decimal form, which gives us 55.0833.... Divide this number by two, and that is your answer. The average speed of the train is 29.04 KPH (This number is rounded to the nearest hundreth- be sure to make a note of that on your answer sheet)
If the outer was the out of the data set it would make it “decrease”
1/3(n - 1/3) = 1/6n
1/3n - 1/9 = 1/6n
-1/9 = 1/6n - 1/3n
-1/9 = 1/6n - 2/6n
-1/9 = - 1/6n
-1/9 * -6 = n
6/9 = n
2/3 = n
Answer:
1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the engineers are selected is not important, so the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
Desired outcomes:
10 engineers selected from a set of 20.
5 best, from a set of 5.
Other 5, from a set of 20-5 = 15.
Totao outcomes:
10 engineers selected from a set of 20.
Probability:
1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20
