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2 years ago

PLEASE HELP ILL ANKE YOU BRAINLEST

Mathematics

2 answers:

Ksenya-84 [330]2 years ago

8 0

Answer:

Move to the left of the horizontal number line to substract

hodyreva [135]2 years ago

6 0

Answer:

you move to the left on the number line

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The mean of six numbers is 41. If one number is removed, the mean of the five numbers is 46. Find the unknown number.

klasskru [66]

Let n be the sum of all 6 numbers:

In the 1st case n/6 = 41 ==> n =246

in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230

= 16

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3 years ago

The answer is 8 but how do you solve it<br><br> 6-2(3-4)

Neko [114]

Start with the parentheses

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2 years ago

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A relay race is 1/10 kilometer long. Four athletes will run an equal distance to complete the relay. How far does each athlete r

Over [174]

25 metres. Because 1/10th of a kilometre is a 100 metres. And four athletes divided by 100 metres is 25 metres.

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2 years ago

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Slope = 2; (-1,4)<br><br> Gghhhgggggghgehwjwjwjwjwjwjw

krok68 [10]

The slope intercept form is given as y = 2x + 6

The general expression for slope intercept form is given as:

y = mx + c

where, m = slope

c = intercept

The formula for slope intercept form when we have been given the coordinates of a point and slope is given as :

$(y-y_{1}) = m(x-x_{1})$ (1)

where ( $x_{1} , y_{1})$ = the coordinates of a point

m = slope of the line

putting the required values in equation (1) we get

(y - 4) = 2(x- (-1))

(y - 4) = 2(x+1) [As (-)*(-) = +]

y - 4 = 2x + 2

y = 2x + 2 + 4

y = 2x + 6

Thus the slope intercept form is y = 2x + 6

Learn more about slope intercept form here : brainly.com/question/19440459

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6 months ago

What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

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2 years ago

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