Answer:
See below
Step-by-step explanation:
From noon to 1500 is three hours
train A then travels <u> 3x</u> where x = speed in km/hr
train B only travels for 2.45 hours and covers
<u> 2.45 ( x + 15) </u> where x + 15 is its speed in km/hr
these two values sum to the 300 km distance
3x + 2.45 ( x + 15) = 300
3x + 2.45 x + 36.75 = 300
x = 48.3 km/hr x+15= 63.3 km / hr
It would be 22 x 3.14 = 69.08 i’m pretty sure lolol sorry if i’m wrong
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer: Do you like my Vegito PFP
Step-by-step explanation:
It's pretty cool
This answer would be a cuboid because it has parallel,perpendicular,and diagonal cross sections
