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2 years ago

An employee receives a 2% raise once per year. If the employee's initial salary is $60,000.00, what will

Mathematics

1 answer:

satela [25.4K]2 years ago

8 0

Answer:

The employee's salary after 9 years will be$70800

Step-by-step explanation:

find the % raise of the salary per year:2%×$60000=$1200

Then multiply the raise by the number of years:$1200×9=$10800

finally add the product with the initial salary:$10800+$60000=$70800

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Which of these expressions is equivalent to – 4(5 – 2x)?

Alekssandra [29.7K]

Answer:

-20+8x

Step-by-step explanation:

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2 years ago

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6h + 4 = 8 solve for h

Greeley [361]

Answer: h=4/6

Step-by-step explanation:

6h=8-4

6h=4 /:6

h=4/6

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3 years ago

1,13, 19..<br> Arithmetic, geometric, or neither

rosijanka [135]

Answer:

Neither.

Step-by-step explanation:

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2 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

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ExtremeBDS [4]

Answer:

$\frac{c-3p}{7}$

Step-by-step explanation:

1) 4(2a+p)=c+p+a

2) Expand: 8a+4p=c+p+a

3) subract a and 4p: 7a=c-3p

4) Divide: a= $\frac{c-3p}{7}$

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2 years ago