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Nookie1986 [14]
2 years ago
9

Consider the following word problem. Imagine that Dr. White of the French department, Dr. Black of the English department, and D

r. Brown of the Economics department are talking. There is one woman among these three, and she does not have brown hair. During the conversation,
Mathematics
1 answer:
Anestetic [448]2 years ago
5 0

A word problem is used to solve problems in mathematics without the explicit use of equations initially.

<h3>What is a Word Problem?</h3>

This refers to the use of words to generate an equation that can be solved by mathematical means.

Hence, we can see that because the question is incomplete, we can infer that there is a relationship that exists between Dr. White, Dr. Black, Dr. Brown, and a woman that does not have brown hair, and equality would be used to solve it.

Read more about word problems here:

brainly.com/question/21405634

#SPJ1

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Question 2
fomenos

Answer:

D. (-2,-5), (0, -7), (1, -4)

Step-by-step explanation:

From Function Theory we must remember that range of a function is the set of images related to elements of the domain. In this case, we must find the image of each of the three elements that forms the domain of f(x, y) = (y+2, -x-4), which are: A(x,y) = (1, -4), B(x,y) = (3,-2) and C(x,y) = (0,-1).

Then we proceed to find all elements of range:

A(x,y) = (1, -4)

f(1,-4) = (-4+2,-1-4)

f(1,-4) = (-2,-5)

B(x,y) = (3,-2)

f(3,-2) = (-2+2,-3-4)

f(3,-2) = (0,-7)

C(x,y) = (0,-1)

f(0,-1) = (-1+2,0-4)

f(0,-1) = (1,-4)

Which corresponds to option D.

3 0
3 years ago
What are the domain and range of f (x) = log (x minus 1) 2?.
statuscvo [17]

You can use the definition of logarithm and the fact that a positive number raised to any power will always stay bigger than 0.

The domain of the given function is  {x | x > 1 and a real number }

The range of the given function is \mathbb R (set of real numbers)

<h3>What is the definition of logarithm?</h3>

If a is raised to power b is resulted as c, then we can rewrite it that b equals to the logarithm of c with base a.

Or, symbolically:

a^b =  c \implies b = log_a(c)

Since c was the result of a raised to power b, thus, if a was a positive number, then a raised to any power won't go less or equal to zero, thus making c > 0

<h3>How to use this definition to find the domain and range of given function?</h3>

Since log(x-1) is with base 10 (when base of log isn't specified, it is assumed to be with base 10) (when log is written ln, it is log with base e =2.71828.... ) thus, we have a = 10 > 0 thus the input x-1 > 0 too.

Or we have:

x > 1 as the restriction.

Thus domain of the given function is {x | x > 1 and a real number }

Now from domain, we have:

x >  1\\&#10;x-1 > 0\\&#10;log(x-1) > -\infty\\&#10;log(x-1) + 2 > -\infty\\&#10;f(x) > -\infty (log(x-1) > -infinity since log(0) on right side have arbitrary negatively large value which is denoted by -infinity)

Thus, range of given function  is whole real number set \mathbb R (since all finite real numbers are bigger than negative infinity)

Thus, the domain of the given function is  {x | x > 1 and a real number }

The range of the given function is \mathbb R (set of real numbers

Learn more about domain and range here:

brainly.com/question/12208715

8 0
2 years ago
Which values represent the first two terms of the sequence a1=2 and an=-4(an-1)^2?
cricket20 [7]
<span>a1= (which is the first term.)
 to find the 2nd term you plug in 2 for (an) in the formula given to you. =-4(2-1)^2 *remember an represents the term u are looking for *
 now you start to solve it
 -4(2-1)^2
 -4 (1)^2 .
-4^2 = 16
 so your first two terms are 2 and 16 .</span>
4 0
3 years ago
Ralph is leasing a car worth $24,000 for three years. His leasing company says that the car Ralph is leasing will only be worth
atroni [7]
The answer is C.) 33% i believe. Excuse me if i'm wrong!!!!!
3 0
3 years ago
Read 2 more answers
What is more accurate, mean or average? Explain why.
Airida [17]
It can be viewed different to what is more accurate depending on the relation of this question to another.
3 0
3 years ago
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