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Novay_Z [31]
2 years ago
6

The product of 9 upon 7 and a number is 63. Find the number​

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

heyy Vrooo....

alr ans is 49

Step-by-step explanation:

see let number be x

so as per ques.. product of x and 9/7 = 9x/7

which is 63

so \frac{9x}{7} = 63

9x = 63*7

x = \frac{63*7}{9}

x = 7*7 = 49

Possible to brainliest <3 ?

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Roman55 [17]

(x^3+x^2+x+2) divide by (x^2-1)

We use long division to divide

There is no x term in x^2 -1  so we put 0x

                         x   +    1

                        ----------------------------

x^2+0x-1           x^3+ x^2 + x+ 2

                         x^3+0x^2-x

                         -----------------------------(subtract the bottom from top)

                               x^2 +2x + 2

                               x^2 +0x - 1

                          --------------------------------(subtract the bottom from top)

                                      2x + 3

                    -----------------------------------------    

Quotient : x+1

Remainder : 2x+3

                               


5 0
3 years ago
A squirrel runs 23 feet down a hill to eat an acorn. Then it runs 23 feet up the hill. Write the integer that represents the squ
sdas [7]
The hill means it was already 23 feet above ground and he went and back up so the answer is 23 positive
4 0
3 years ago
Read 2 more answers
I need help with this problem​
balu736 [363]

Answer:

2.1000x10^03

Step-by-step explanation:

7 0
2 years ago
A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

5 0
3 years ago
Graham graphs the following system of equations to determine its solution.
V125BC [204]

Answer: (2,2)

Step-by-step explanation:

I'm going to use substitution to solve this:

First, I use the second equation to solve for y in terms of x.

2x - y = 2

-y = 2 - 2x

y = 2x - 2

Then, I plug the value for y into the first equation:

2x + 4y = 12

2x + 4(2x - 2) = 12

2x + 8x - 8 = 12

10x - 8 = 12

10x = 20

x = 2

Now that we have x, we can plug it into either equation (I used the first) to get the value for y:

2x + 4y = 12

2(2) + 4y = 12

4 + 4y = 12

4y = 8

y = 2

We get the point (2,2) as a solution.

Note: This is the point where both lines intersect.

3 0
3 years ago
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