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2 years ago

Check whether (x-1) is a factor of 2x²-3x+1 or not ................

Mathematics

2 answers:

wariber [46]2 years ago

5 0

Answer: Yes

Step-by-Step Explanation:

Setler79 [48]2 years ago

4 0

Answer:

(x - 1) is a factor of 2x² - 3x + 1

Step-by-step explanation:

<u>Method 1</u>

If (x - 1) is a factor of f(x) = 2x² - 3x + 1 then f(1) = 0

Substitute x = 1 into the equations:

f(1) = 2(1)² - 3(1) + 1

= 2 - 3 + 1

= 0

Therefore, (x - 1) is a factor of 2x² - 3x + 1

<u>Method 2</u>

Factor 2x² - 3x + 1

Find 2 two numbers that multiply to 2 and sum to -3: -2 and -1

Rewrite the coefficient of the middle term as the sum of these 2 numbers:

⇒ 2x² - 2x - x + 1

Factorize the first two terms and the last two terms separately:

⇒ 2x(x - 1) - 1(x - 1)

Factor out the common term (x - 1):

⇒ (2x - 1)(x - 1)

Thus proving that (x - 1) is a product of 2x² - 3x + 1

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

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2 years ago

500 grams of tomatoes cost £1.76 how much will 1.75kg cost??

ValentinkaMS [17]

500 grams equals 0.50 kg so multiply 1.76 3 times to get 5.28, then divide 1.76 by 2 to get .88 add the two together to get 6.16

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3 years ago

Please, Help with this MATH question.

hammer [34]

Y in the second equation

6 0

2 years ago

Read 2 more answers

There are four steps in the manufacturing process of a stuffed toy: cutting, stuffing, sealing, and packaging. There are two emp

Anit [1.1K]

Answer:

(a) 2min/15units

(b) 1min/20units

(d) The capacity of the new employee should be 1unit/2sec. The process capacity will increase four times

Step-by-step explanation:

(a) Cycle time for stage cutting for 2 employees = 16sec/2units × 1min/60sec = 2min/15units

(b) Cycle time for stage sealing for 1 employee = 3sec/1unit × 1min/60sec = 1min/20units

(d) If the capacity of the new employee is 1unit/2sec, the process capacity = 1unit/2sec × 3600sec/1hour = 1800units/hour. The process capacity increases 4 times (1800/450 = 4)

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3 years ago

a 5-gallon mixture contains 40% acid. A 3-gallon mixture contains 50% acid. what percent acid is obtained by putting the two mix

natta225 [31]

so the 5 gallons ones is 40% acid, how much acid solute is in it anyway? well just 40% of 5 or namely 0.4*5 = 2 gallons.

the 3 gallons one is 50%, likewise it has 0.50 * 3 = 1.5 gallons of acid solute in it.

$\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{gallons of }}{amount}\\ \cline{2-4}&\\ \textit{1st mixture}&5&0.4&\stackrel{(5)(0.4)}{2}\\ \textit{2nd mixture}&3&0.5&\stackrel{(3)(0.5)}{1.5}\\ \cline{2-4}&\\ mixed&8&p&3.5 \end{array} \\\\\\ 8p=3.5\implies p=\cfrac{3.5}{8}\implies p=0.4375\implies p=\stackrel{\%}{43.75}$

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2 years ago

Check whether (x-1) is a factor of 2x²-3x+1 or not ................ ​

Check whether (x-1) is a factor of 2x²-3x+1 or not ................