Answer:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)
Step-by-step explanation:
Given

Required
Convert to radical form

Evaluate the exponents


Split the exponent

Apply the following law of indices
![(x^a)^\frac{1}{b} = \sqrt[b]{x^a}](https://tex.z-dn.net/?f=%28x%5Ea%29%5E%5Cfrac%7B1%7D%7Bb%7D%20%3D%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
So, we have:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)
Answer:
Number of year in which population will be 180,000 = 6 year (Approx.)
Step-by-step explanation:
Given:
Population in 2007 = 168,979
Rate of increase in population = 1% = 0.01
Future population = 180,000
Find:
Number of year in which population will be 180,000
Computation:
A = P[1+r]ⁿ
Future population = Population in 2007[1+Rate of increase in population]ⁿ
180,000 = 168,979[1+0.01]ⁿ
180,000 = 168,979[1.01]ⁿ
1.06522 = [1.01]ⁿ
n = 6 (Approx.)
Number of year in which population will be 180,000 = 6 year (Approx.)
1/12 each night
I cant draw a picture here but you can draw 4 circles and divide them each into 3 equal parts
Answer:
f(x) = 2x(x - 8)
f(x) = 2(x - 2)² - 8
Step-by-step explanation:
Let the equation of the quadratic function is,
f(x) = a(x - h)² + k
Here, (h, k) is the vertex of the function.
From the graph attached,
Vertex of the parabola → (2, -8)
Therefore, equation of the function will be,
f(x) = a(x - 2)² - 8
Since, the graph passes through origin (0, 0),
f(0) = a(0 - 2)² - 8
0 = 4a - 8
a = 2
Equation of the given parabola will be,
f(x) = 2(x - 2)² - 8
= 2(x² - 4x + 4) - 8
= 2x² - 8x + 8 - 8
= 2x² - 8x
= 2x(x - 8)
Therefore, factored form of the function will be,
f(x) = 2x(x - 8)