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Travka [436]
3 years ago
12

X-y=6 and x=y-2; solve by substitution

Mathematics
2 answers:
Novay_Z [31]3 years ago
6 0

Answer: No Solution


Step-by-step explanation: You plug in x=y-2 into x-y=6. So the problem would be rearranged into (y-2)-y=6. When done correctly the y's cancel out making it a no solution.


IceJOKER [234]3 years ago
3 0

The solution is  

x

=

4

,

y

=

2

Explanation:

x

+

y

=

6

....equation  

1

x

−

y

=

2

.......equation  

2

Solving by elimination.

Adding equations  

1

and  

2

x

+

y

=

6

x

−

y

=

2

2

x

=

8

x

=

4

Finding  

y

by substituting  

x

in equation  

1

x

+

y

=

6

y

=

6

−

x

y

=

6

−

4

y

=

2Step-by-step explanation:


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6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
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Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

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