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Travka [436]
3 years ago
12

X-y=6 and x=y-2; solve by substitution

Mathematics
2 answers:
Novay_Z [31]3 years ago
6 0

Answer: No Solution


Step-by-step explanation: You plug in x=y-2 into x-y=6. So the problem would be rearranged into (y-2)-y=6. When done correctly the y's cancel out making it a no solution.


IceJOKER [234]3 years ago
3 0

The solution is  

x

=

4

,

y

=

2

Explanation:

x

+

y

=

6

....equation  

1

x

−

y

=

2

.......equation  

2

Solving by elimination.

Adding equations  

1

and  

2

x

+

y

=

6

x

−

y

=

2

2

x

=

8

x

=

4

Finding  

y

by substituting  

x

in equation  

1

x

+

y

=

6

y

=

6

−

x

y

=

6

−

4

y

=

2Step-by-step explanation:


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Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
3 years ago
Need help solving this problem ​
natka813 [3]

Answer:

Part 1: \frac{11-x}{5} or \frac{11}{5}-\frac{x}{5}

Part 2: \frac{9}{5}

Step-by-step explanation:

To start things off, you must put everything on the opposite side of y so that you only have the y variable left.

In this case, put x onto the other side, making it negative since it's flipped, so you get 5y=11-x (since the x is negative you're using subtraction from 11).

Next, divide both sides by 5 to make 5y into y:

\frac{5y}{5} =\frac{11}{5}-\frac{x}{5}

y=\frac{11}{5}-\frac{x}{5}

Then in this case you turn y=f(x), but the system did it for you, so all you have to put is \frac{11}{5}-\frac{x}{5}.

For the second part you must replace x with 2 since you need to find f(2).

\frac{11-2}{5}

Your answer for part 2 is \frac{9}{5}.

3 0
2 years ago
A cylindrical water tank is being filled with a hose. The depth of the water increases by 1 1/4 ft per hour.
Ray Of Light [21]
2 4/5 is the correct answer
6 0
3 years ago
Simplify (b^4)^3 A.B^9 B.B^3 C.B D.B^12
natulia [17]

(b^4)^3


To simplify when something is raised to two different exponents, multiply the two exponents together:

4 * 3 = 12

You now have b^12.


The answer is D.


6 0
3 years ago
Plot the x- and y-intercepts to graph the equation. y=−12x−3
Lisa [10]
X-intercept; -.25
y-intercept; -3
8 0
2 years ago
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