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katovenus [111]
2 years ago
14

5. The heights of 500 female students are measured, half of whom are college students and half of whom are second-grade students

. How many modes would you expect for this distribution? Why? Would this distribution be symmetric, left-skewed, right-skewed or none of these? Why?
Mathematics
1 answer:
AysviL [449]2 years ago
4 0

Using statistical concepts, it is found that:

  • 2 modes would be expected for the distribution.
  • The distribution would be symmetric.

-------------------------------

  • Heights are traditionally normally distributed, which is a symmetric distribution.
  • Second-grade students are considerably shorter than college students, so there would be two modes.
  • Both distributions, for the height of second grade and of college students, are normal, which is symmetric, thus the combined distribution will also be symmetric.

A similar problem is given at brainly.com/question/13460485

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Answer:

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Step-by-step explanation:

OK lets try again.

The slope of the secant = slope of the tangent at a certain point ( The Mean Value Theorem).

Slope of the secant = f(5) - f(2) / (5 - 2)

= [(25-3) / (5-1)  - (4-3) / (2-1)] / 3

=  (22/4 - 1) / 3

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The derivative at c = the slope of the tangent at c.

Finding the derivative:

f'(x) =  [2x(x - 1) - (x^2 - 3) ]/ (x - 1)^2    (where x = c).

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So equating the slopes:

(x^2 - 2x + 3) / (x - 1)^2 = 3/2

2x^2 - 4x + 6 = 3x^2 - 6x + 3

x^2 - 2x - 3 = 0

(x - 3)(x + 1) = 90

x = 3 , -1

x can't be -1 because we are working between the values 2 and 5 so

x = c = 3.

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