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nirvana33 [79]
3 years ago
15

The coughlin family discovered they can stand in a row for their family portrait in 720 diferent ways. How many members are in t

he coughlin family
Mathematics
1 answer:
Alex3 years ago
6 0

There are <em>six</em> (6) members of the family.

The first person in the row can be any 1 of the 6.  For each choice . . .
The 2nd person in the row can be any 1 of the other 5.  For each choice . . .
The 3rd person in the row can be any 1 of the other 4.  For each choice . . .
The 4th person in the row can be any 1 of the other 3.  For each choice . . .
The 5th person in the row can be any 1 of the other 2.  For each choice . . .
The 6th person in the row is the 1 who is left.

Total number of ways to line up = (6 x 5 x 4 x 3 x 2 x 1) = 720 ways .

This number is called " six factorial ", and it's written ' 6! ' .


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Answer:

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Step-by-step explanation:

<em>The </em><em>equation</em><em> </em><em>of </em><em>line </em><em>is </em><em>given </em><em>by </em>

<em>first </em><em>we </em><em>can </em><em>find </em><em>slope </em><em>(</em><em>m</em><em>) </em>

<em>=</em><em> </em><em>(</em><em>y2 </em><em>-</em><em> </em><em>y</em><em>1</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>x2</em><em> </em><em>-</em><em> </em><em>x1</em><em>)</em>

<em>=</em><em> </em><em>3</em><em>4</em><em>-</em><em>1</em><em>0</em><em>/</em><em>1</em><em>0</em><em>+</em><em>1</em>

<em> </em><em>=</em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em>

<em>Now </em><em>the </em><em>equation </em><em>is</em>

<em>y </em><em>-</em><em> </em><em>y1 </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em><em> </em><em>(</em><em> </em><em>x </em><em>+</em><em>1</em><em>1</em><em>)</em>

<em>11 </em><em>(</em><em> </em><em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em> </em><em>(</em><em>x </em><em>+</em><em> </em><em>1</em><em>1</em><em>)</em>

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