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kogti [31]
2 years ago
15

I don’t understand this, can someone please explain and show the answers please

Mathematics
1 answer:
OLga [1]2 years ago
3 0

your answer would be A. 122/27

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2.<br>2x2 + 2x - 112 factor​
Angelina_Jolie [31]

Answer:

Use order of operation

Step-by-step explanation:

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3 years ago
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The Kansas predicted that in 2018 the population in Centerville would be 17,466 and actuality it was 16,400 what is the percent
sammy [17]

Answer:

6.5%

Step-by-step explanation:

Percentage error formula =

|Estimated value - Real value|/Real value × 100

From the above question,

Estimated value = 17,466

Real value = 16,400

Percentage error = |17,466 - 16,400|/16,400 × 100

= 1066/16,400 × 100

= 0.065 × 100

= 6.5%

Therefore, the percent error = 6.5%

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What is 10x as much as 70?​
sleet_krkn [62]

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Answer:

  700

Step-by-step explanation:

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  10×70 = 700

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What is 8.545 kg to the nearest hundredth And the nearest tenth?
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3 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
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