The answer is -4 final answer
Volumen of A Solid
Given a solid with a shape of a constant base B and height H, the volume is:
V = BH
The height of the solid is 1 1/4 ft. We need to calculate the area of the base.
The base consists of a larger rectangle from which has been taken a smaller rectangle.
The larger rectangle has dimensions of 9 ft by 6 ft, thus its area is:
A1 = 9 ft * 6 ft = 54 square ft
The smaller rectangle has dimensions of 2 1/2 ft by 4 ft.
The second dimension was calculated as the difference between 9 ft and 2 ft plus 3 ft. (9 ft - 3 ft - 2 ft = 4 ft).
The area of the smaller rectangle is:
A2 = 2 1/2 * 4
The mixed fraction 2 1/2 is converted to improper fraction:
2 1/2 = 2 + 1/2 = 5/2
Thus, the area is:
A2 = 5/2 * 4
A2 = 10 square feet
The area of the base is A1 - A2 = 54 square feet - 10 square feet = 44 square feet
B = 44 square feet.
Now for the volume:
V = 44 square feet * 1 1/4 feet
Again the mixed fraction is converted to a single fraction:
1 1/4 = 1 + 1/4 = 5/4
V = 44 square feet * 5/4 feet
V = 55 cubic feet
Answer:
Step-by-step explanation:
From the question we are told that:
Dimension of ABC
A=9
B=11
C=110
Dimension of FED
D=231
Generally the equation for the similar triangles is mathematically given by
Therefore solving for F
Therefore solving for E
Measure of 
Measure of 
Answer:
5b - 5a
Step-by-step explanation:
b(5 - a) = 5b - ab
- a(b - 5) = - ab + 5a
Subtracting gives
5b - ab - (- ab + 5a) ← distribute parenthesis by - 1
= 5b - ab + ab - 5a ← collect like terms
= 5b - 5a
