3 years ago

Solve for t.3/4t = 1/4

Mathematics

1 answer:

Vlad1618 [11]3 years ago

3 0

I hope this helps you

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M ∠4 = 2x°, m ∠2 = (4/3)x°, m ∠3 = 20°, find x.

anygoal [31]

The answer is c, b/c...

20+(4/3)x=2x

-(4/3)x -(4/3)x

20=(2/3)x

20/(2/3)=(2/3)x/(2/3)

A: 30=x

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4 years ago

ILL GIVE BRAINIEST TO WHOEVER IS CORRECT!! PLEASE HELP ASAP!!

IrinaK [193]

Answer:

a) angle CAR =angle BAR

Im so sorry if im wrong

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3 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 7.3\text{ ft}7.3 ft and the height of the py

Cloud [144]

Answer:

$V=6.66\ ft^3$

Step-by-step explanation:

The perimeter of the square base of a pyramid = 7.3 ft

The height of the pyramid, h = 6ft

The perimeter of a square is given by :

P = 4s, s is the side of square

7.3 = 4s

s = 1.825 ft

The volume of a pyramid is given by :

$V=\dfrac{lbh}{3}$

Here, l = b = 1.825 ft

So,

$V=\dfrac{1.825\times 1.825\times 6}{3}\\\\V=6.66\ ft^3$

So, the volume of the pyramid is equal to $6.66\ ft^3$ .

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3 years ago

the angle of elevation from a viewer to the top of a flagpole is 50°. the viewer is 40 ft away and the viewers eyes are 5.5 ft f

Margarita [4]

Answer:

53.2 feet

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

$tan(50^o)=\frac{AC}{BC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(50^o)=\frac{h}{40}$

solve for h

$h=(40)tan(50^o)$

$h=47.7\ ft$

therefore

The height of the pole is

$h+5.5=47.7+5.5=53.2\ ft$

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3 years ago

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x?

Nataliya [291]

First factor out a variable: x(x^2-2x-24)
now solve the quadratic: x(x-6)(x+4)
When you set these expressions equal to zero, you get 0, 6, and -4 as your answers.

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3 years ago

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