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3 years ago

Please i need the answer

Mathematics

1 answer:

Harrizon [31]3 years ago

7 0

Answer: b
sorry cant give explanation

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Approximate the sum of the convergent infinite series the least usingnumber of terms so that the error is less than .0001. What

____ [38]

Solution :

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ $a_n= \frac{(-1)^n}{n ! 2^n} \ \ \ \ \ a_{n+1}= \frac{(-1)^{n+1}}{(n+1) ! 2^{n+1}}$

Error = $|a_{n+1}|$

Error ≤ 0.0001

$|\frac{(-1)^{n+1}}{(n+1)!2^{n+1}}| \leq 0.0001$

$|\frac{1}{(n+1)!2^{n+1}}| \leq 10^{-4}$

$(n+1)! 2^{n+1} \geq 10000$

Now try, n ≥ 5

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\sum_{n=1 }^{5 } \frac{(-1)^n}{n ! 2^n}$ (with error 0.0001)

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\frac{-1}{1!2}+\frac{1}{2!2^2}-\frac{1}{3! 2^3}+\frac{1}{4! 2^4}-\frac{1}{5! 2^5}$

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = 0.6065104

3 0

3 years ago

88.4×10^3 in standard notation

scoray [572]

88.4*10^3 is = 88.4*10*10*10 =88400

Hope this helps! Any questions please just ask! Thank you!

8 0

3 years ago

A training program is used by a corporation to direct hirees to appropriate jobs. The program consists of two steps.

AlekseyPX

The probability is the probality of being designated a a management trainee (i.e. 30%) * the probability of not be appointed to a management posittion (i.e. 25%, which comes from 20% to be assigned to nonmanagerial position + 5% of being fired).

Result: 30% * 25% = 7.5%.

Answer: 7.5%.

4 0

3 years ago

8 + z = 19. step equations

steposvetlana [31]

Answer:

Step-by-step explanation:

First subtract

19-8= Z

So solution would be

Z=11

7 0

3 years ago

Read 2 more answers

Help pleas eldkjsdweggrwsddwsf

Cloud [144]

I agree with the top guy

7 0

2 years ago