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lakkis [162]
3 years ago
14

Please i need the answer

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0
Answer: b
sorry cant give explanation
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Solve the following equation: 9x-14=22
katrin2010 [14]

Answer:

x=4

Step-by-step explanation:

9x=36, divide both sides by 9

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4 years ago
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PLZZZZ I NEEED HELP!!!<br><br><br> I said please
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Step-by-step explanation:

Angle 128 ° + Angle Y = 180 °

Y = 180 - 128

= 52 °

5x + 3 + Y = 180

5x + 3 + 52 = 180

5x + 55 = 180

5x = 180 - 55

5x = 125 °

x = 125 ÷ 5

x = 25

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The set of coordinates represent B.Rectangle.
5 0
4 years ago
Whiskers the cat weighs 2 and 2 over 3 kg.piglio weighs 4 kg. How many times as heavy as piglio is whiskers
ruslelena [56]

Answer:

Whiskers is two-third times as heavy as piglio is.

Step-by-step explanation:

Given:

Weight of whiskers is, W=2\frac{2}{3}\ kg

Weight of piglio is, P=4\ kg

In order to compare their weights, we have to divide both the weights and then express one weight in terms of the other.

Therefore, dividing whiskers weight by piglio's weight, we get:

\frac{W}{P}=2\frac{2}{3}\div 4\\\frac{W}{P}=\frac{8}{3}\div \frac{4}{1}(\textrm{4 can be rewritten as 4/1 in fraction form})

Now, when we divide two fractions, we replace the division sign by multiplication and reverse the second fraction. This gives,

\frac{W}{P}=\frac{8}{3}\times \frac{1}{4}\\\frac{W}{P}=\frac{8\times 1}{3\times 4}\\\frac{W}{P}=\frac{2}{3}

Now, expressing 'W' in terms of 'P', we multiply both sides by 'P. This gives,

W=\frac{2}{3}P

Therefore, the weight of whiskers is two-third times as heavy as piglio is.

4 0
3 years ago
National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea
kirill115 [55]

Answer:

The required expression is y=250,000-24,000 t

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m=\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}

Rate of change=m=\frac{Rise}{Run}=\frac{-240,000}{10}

Rate of change=m=\frac{Rise}{Run}=-24,000

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

(y-250,000)=-24,000(t-0)

y-250,000=-24,000 t

y=250,000-24,000 t

Hence, the required expression is y=250,000-24,000 t

6 0
3 years ago
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