At the end of three days, 
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒ 
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒ 
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒ %
Therefore , At the end of three days, % of the original amount of liquid remains in Kyle's container .
Answer:
456
Step-by-step explanation:
Let X be the SATscore scored by the students
Given that X is normal (1000,200)
By converting into standard normal variate we can say that
is N(0,1)
To find the top 10% we consider the 90th percentile for z score
Z 90th percentile = 1.28
i.e. only students who scored 456 or above only should be considered.
Y= -1/4x + 4.25, perdendicular then it must be the opposite of 4x which is -1/4. Then you multiply it with 5 and then add or subtract a number so you can find 3. So -1/4× 5 + 4.25= 3. Here you gooo!
The results of the experiment are shown in the frequency side
a) 14
b) 3600 Best guess 300*12
Answer:
=14bx2−7x3−4b+2x
Step-by-step explanation:
