Question

Please help me with this

Answer 1

Answer:

Find the hypotenuse of the triangle, and that will help a lot!

Step-by-step explanation:

Pythagorean Theorem: a^2 + b^2 = c^2 (Where c is the hypotenuse)

Here we have two leg lengths, 3 and 8.

We can put it in the formula, where it would look something like this:

3^2 + 8^2 = c^2

After simplifying, you would get that c = $\sqrt{73}$

Now for the trig functions:

your adjacent leg would be 8, opposite leg would be 3, and hypotenuse $\sqrt{73}$

cos θ = adj/hyp (your θ should be on the bottom left i think)

cos  = 8/$\sqrt{73}$

sin  =  7/$\sqrt{73}$

tan   = 3/8

sec = $\sqrt{73}$/8

csc = $\sqrt{73}$/3

I don't know what the sixth one would be, but those are the five main ones.