The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
Answer:
136 
Step-by-step explanation:
Well if you find the lateral area (the area of the rectangles on the sides) to get 112, so you just need to add that to the triangles and for those (they add up to 36) you can just use the formula for the area of a triangle, which is 
.
Hope this helps :)
Peggy has 12 practice sessions
The first step is finding the unit rate. We can do this by evaluating
21/1.75 divided by 1.75/1.75.
When you divide the two, you get 12.
To check your work you do 12(1.75) and you will get 21
Answer: the amount a person pays for gas compared with the number of gallons purchased
Step-by-step explanation:
